Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
Both Lindsay and Sharon are wrong.
Step-by-step explanation:
When Lindsay was doing her problem, she put 100 on the bottom and 45 on the top, when it should have been the other way around.
Sharon would have been correct if she had used the right measuring unit. 2/5 of a milliliter should have been 2/5 of a liter.
Answer:
the range is 5-8 hours
Step-by-step explanation:
325+175t=1200
175t=875
875/175
t=5
325+175t=1725
175t=1400
1400/175
t=8
X=0.697
x=4.30
Hope this helps
Remember that x/4 and 1/4*x is the same thing.
1/4*52 is therefore the same as 52/4. Fractions represent division, so 52 divided by 4 is also correct.
0.25*x is the same as 1/4*x because 1/4=0.25
4% of 52 is incorrect because the decimal form of 4% is 0.04, which is not the same as 0.25
Final answer: B
