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Anna35 [415]
4 years ago
9

0.14356712341 what kinda number is it

Mathematics
1 answer:
Digiron [165]4 years ago
8 0

it is an irrational not sure but i don't believe that it could be put in an ratio, so I say an irrational number

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1.)/6h=30 check: 2.) 50=c-21 check: 3.) d/10 =9. check:
Thepotemich [5.8K]

1. h=5

2. -0.42

is the answers to 1 and 2 i believe i am working on 3


3 0
4 years ago
PLEASE HELP!!!!<br> WILL GIVE BRAINLIEST!!!!!!!
kkurt [141]

Answer:

56 miles

Step-by-step explanation:

7 0
3 years ago
Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well
Jlenok [28]

Answer:

Clay's finishing time is 1.68 standard deviation above the mean finishing time for men.

Step-by-step explanation:

In statistics, a standardized score is the number of standard deviations an observation or data point is from the mean.

Let us consider a random variable, X that follows a normal distribution, N (<em>µ</em>, <em>σ</em>²).

Then <em>Z</em> is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is,

Z=\frac{x-\mu}{\sigma}\sim N(0, 1)

This, <em>z</em>-score is known as the standardized score.

It is provided that the distribution of finishing time for men (say, <em>X</em>) was approximately normal with mean <em>µ</em> = 242 minutes and standard deviation <em>σ = </em>29 minutes.

The finishing time for Clay was <em>x</em> = 289 minutes.

Compute Clay's <em>z</em>-score as follows:

Z=\frac{x-\mu}{\sigma}

   =\frac{289-242}{29}\\\\=1.67857143\\\\\approx 1.68

Thus, Clay's standardized score is 1.68.

That is, Clay's finishing time is 1.68 standard deviation above the mean finishing time for men.

7 0
3 years ago
The owner of a 4000-gal oil truck loads the truck with gasoline and keroseno. The profit on each gallon of gasoline is 16e and o
lilavasa [31]

Answer:

There were 35 gallons of gasoline and 500 gallons of kerosene.

Step-by-step explanation:

<u>Step 1: Write data for equation 1</u>

<em>Let gallons of kerosene be x</em>

<em>Let gallons of gasoline be y</em>

<em>Total capacity of truck is 4000</em>

<u>Step 2: Form equation 1</u>

x + y = 4000

<u>Step 3: Write data for equation 2</u>

<em>Profit of total gallons of kerosene is 0.12x</em>

<em>Profit of total gallons of gasoline is 16y</em>

<em>Total profit is $620</em>

<u>Step 4: Form equation 2</u>

0.12x + 16y = 620

<u>Step 5: Find x in terms of y from equation 1</u>

x + y = 4000

x = 4000 - y

<u>Step 6: Substitute value of x in equation 2</u>

0.12x + 16y = 620

0.12 (4000 - y) + 16y = 620

480 - 12y + 16y = 620

4y = 620 - 480

y = 140/4

y = 35

<u>Step 7: Substitute value of y in equation 1 to find x</u>

0.12x + 16y = 620

0.12x + 16 ( 35 ) = 620

0.12x = 60

x = 500

There were 35 gallons of gasoline and 500 gallons of kerosene.

!!

6 0
3 years ago
Alfonso makes $8.00 per hour working at a movie theater and $12.00 per hour working at a restaurant. Next week, Alfonso is sched
aksik [14]
(8 x 6) 8h =144
48+ 8h=144
144-48= 96
8h=96
96 divided by 8= 12
So he should have to work 12 hours at the restaurant. Hope this helps and sorry if it’s wrong!
8 0
4 years ago
Read 2 more answers
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