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2 years ago

8

What is the first step that a smart new-car buyer should take before talking to salespersons and putting a deposit on a car?

1 answer:

4vir4ik [10]2 years ago

7 0

Researching online to find the best stuff for it's value
ex. try to find the best kind of car that you can buy with the least amount of money
researching by yourself is important because you will know alot and if the salesperson says all good things about a product, you might know some downsides and mentally be prepared lest you get a car you don't like

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Find the 75th term of the following6, 10, 14, 18,

enot [183]

Given the sequence:

6, 10, 14, 18,...

We will find the 75th term

The given sequence is an arithmetic sequence

Because there is a constant common differnce

d = 18 - 14 = 14 - 10 = 10 - 6 = 4

The first term = a = 6

The general formula of the arithmetic sequence is as follows:

$a_n=a+d(n-1)$

Where: n is the nth term

To find the 75th term, substitute with n = 75 and a = 6, d = 4

$a_{75}=6+4\cdot(75-1)=302$

So, the answer will be the 75th term = 302

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9 months ago

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A is increasing , b is maximum , c is decreasing, and d is minimum

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2 years ago

Ethan was feeling adventurous at lunch. Rather than choosing a single drink, he decided to mix together all the drink choices. H

jarptica [38.1K]

Answer:

1.7

Step-by-step explanation:

I divided 7 by 12 to get 1.7. Each soda gets at least 1 ounce.

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2 years ago

Read 2 more answers

For the cost function c equals 0.1 q squared plus 2.1 q plus 8, how fast does c change with respect to q when q equals 11? Det

Soloha48 [4]

Answer:

Rate of change of c with respect to q is 4.3

Percentage rate of change c with respect to q is 9.95%

Step-by-step explanation:

Cost function is given as, $c=0.1\:q^{2}+2.1\:q+8$

Given that c changes with respect to q that is, $\dfrac{dc}{dq}$ . So differentiating given function,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left (0.1\:q^{2}+2.1\:q+8 \right)$

Applying sum rule of derivative,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left(0.1\:q^{2}\right)+\dfrac{d}{dq}\left(2.1\:q\right)+\dfrac{d}{dq}\left(8\right)$

Applying power rule and constant rule of derivative,

$\dfrac{dc}{dt}=0.1\left(2\:q^{2-1}\right)+2.1\left(1\right)+0$

$\dfrac{dc}{dt}=0.1\left(2\:q\right)+2.1$

$\dfrac{dc}{dt}=0.2\left(q\right)+2.1$

Substituting the value of $q=11$ ,

$\dfrac{dc}{dt}=0.2\left(11\right)+21.$

$\dfrac{dc}{dt}=2.2+2.1$

$\dfrac{dc}{dt}=4.3$

Rate of change of c with respect to q is 4.3

Formula for percentage rate of change is given as,

$Percentage\:rate\:of\:change=\dfrac{Q'\left(x\right)}{Q\left(x\right)}\times 100$

Rewriting in terms of cost C,

$Percentage\:rate\:of\:change=\dfrac{C'\left(q\right)}{C\left(q\right)}\times 100$

Calculating value of $C\left(q \right)$

$C\left(q\right)=0.1\:q^{2}+2.1\:q+8$

Substituting the value of $q=11$ ,

$C\left(q\right)=0.1\left(11\right)^{2}+2.1\left(11\right)+8$

$C\left(q\right)=0.1\left(121\right)+23.1+8$

$C\left(q\right)=12.1+23.1+8$

$C\left(q\right)=43.2$

Now using the formula for percentage,

$Percentage\:rate\:of\:change=\dfrac{4.3}{43.2}\times 100$

$Percentage\:rate\:of\:change=0.0995\times 100$

$Percentage\:rate\:of\:change=9.95%$

Percentage rate of change of c with respect to q is 9.95%

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2 years ago

The triangle below is isosceles. Find the length of side x in simplest radical form with

Grace [21]

Step-by-step explanation:

it's the square equal to the equivalent equation to equal 5 673y

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2 years ago