2+3t
When t is 1
2+3(1)
2+3
5
When t is 4
2+3(4)
2+12
14
Answer:
<h2>x= 37/16</h2><h3>
y=199/8</h3>
Step-by-step explanation:
1....y=11+6x
-77-2x+3y=-7
replace y by ..1..
so -77-2x+3(11+6x)=-7
-77-2x+33+18x=-7
-44+16x=-7
16x=37
y=11+6x
replace x by 37/16
y=11+6*37/16
y=199/8
Answer:
-5^ -1 = 1/(-5) = -1/5
-1/y^(-4) = -(1/(1/y^4)) = -y^4
5^4 x 5^7 = 5^(4 + 7) = 5^11
Hope this helps!
:)
Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;
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The "coefficient" of the "a" term is: " - 12" .
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The "constant" is: " 32 " .
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Explanation:
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Let: "a = x² + 4 " .
Given: (x² + 4)² + 32 = 12x² + 48 ;
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Factor: "12x² + 48" into " (x² + 4) " ;
"12x² + 48" = 12 (x² + 4) " ;
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Given: (x² + 4)² + 32 = 12x² + 48 ;
rewrite as; "a² + 32 = 12a " ;
Subtract "12a" from each side of the equation;
"a² + 32 - 12a = 12a - 12a ;
to get:
" a² - 12a + 32 = 0 " .
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The coefficient of the "a" term; that is:
The "coefficient" of " -12a" ; is: "- 12" .
The constant is: "32<span>" .
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