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aleksandrvk [35]
3 years ago
15

Simplify when it is possible 10 x^2 - y + x^2

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
Combine like terms
11x^2 - y
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NEED ASAP WILL GIVE BRAINLIEST Write a real world problem that can be represented by the following inequality, 15X - 20 ≤ 130 ,a
ddd [48]

Answer:

I used my name, lol

Step-by-step explanation:

Kat wants to use her money to support animals at a shelter after receiving her pay check from work . She pays $15 per animal, and leaves $20 for the workers. She can spend at most $130. How many animals can she help?

Solve for x

15x-20\leq 130

Add 20 to both sides to isolate x

15x-20+20\leq 130+20\\15x\leq 150

Divide each side by 15

\frac{15x}{15}\leq  \frac{150}{15} \\\\x\leq 10

Kat can help at most 10 animals.

(I am so sorry I took so long, I couldn't come up with anything.)

5 0
3 years ago
Write the following statement as a conditional statement.
____ [38]

Answer:

If a figure has four sides, then it is a kites.

Step-by-step explanation:

5 0
3 years ago
Which equation is best represented by the graph above (x+1)(x-3)(x+2). please explain why
Nat2105 [25]
<h3>Answer:</h3>

y = (x +2)(x -1)(x -3) . . . . or . . . . y = x³ -2x² -5x +6

<h3>Step-by-step explanation:</h3>

The graph shows y=0 at x=-2, x=1, and x=3. These are called the "zeros" or "roots" of the function, because the value of the function is zero there.

When "a" is a zero of a polynomial function, (x -a) is a factor. This means the factors of the graphed function are (x -(-2)), (x -1) and (x -3). The function can be written as the product of these factors:

... y = (x +2)(x -1)(x -3) . . . . . the equation represented by the graph

Or, the product can be multiplied out

... y = (x +2)(x² -4x +3)

... y = x³ -2x² -5x +6 . . . . . the equation represented by the graph

7 0
3 years ago
Suppose I have Rs 1000 and I put it in the bank. What will be the amount I have after 5 years if Interest is 5% per annum?​
vichka [17]

Answer:

Its 250 the answer which i got.

8 0
2 years ago
Read 2 more answers
A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>.  Thus

C=4x+4y+4y+16x\\C=20x+8y

We know that the total area of rectangular field should be 2250 square yards,

x\cdot y=2250

We can say that y=\frac{2250}{x}

Substituting into the total cost of the rectangular field, we get

C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

We have to figure out where the function is increasing and decreasing. Differentiating,

\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}

Next, we find the critical points of the derivative

20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0
3 years ago
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