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Troyanec [42]
3 years ago
8

What is the result if you divide

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0
( 18r^4 × s^5 × t^6 ) / ( -3r^2 × s × t^3 )
=
-6r^2 × s^4 × t^3
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Bananas cost $ 0.59 per pound.Write an equation that could be used to find the total cost,y,of x pounds of bananas.​
maks197457 [2]
I think it is 5 Bc I do and if you got to know so bad
4 0
3 years ago
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Which expression has the greatest value |-21|, |14|, |30|, |-45|
tresset_1 [31]

Answer:

|-45|

Step-by-step explanation:

In mathematics, the absolute value of a real number is the numeric value of the  number, regardless the sign, either this is positive or negative.

The absolute value function can be definied as:

  • |a|=a si a ≥0
  • |a|=-a si a <0

Using this definition, we have:

|-21| = -(-21) = 21

|14| = 14

|30| = 30

|-45| = -(-45) = 45

Therefore, the expression |-45| has the greatest value.

3 0
3 years ago
66 is 75% of what number?
Anon25 [30]
88 is what it is 75% of

6 0
2 years ago
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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 (5
Blizzard [7]

Answer:

B = 61.75°

Step-by-step explanation:

The formula for the Law of Sines is given as:

a/ sin A = b/ sin B

In the question, we are given the following values

A = 56°, a = 16, b = 17

We are to solve for B

Hence,

16/ sin 56° = 17/sin B

Cross Multiply

sin B × 16 = sin 56° × 17

sin B = sin 56° × 17/16

sin B = 0.88

B = arc sin(0.88)

B = 61.74536°

Approximately B = 61.75°

7 0
3 years ago
A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates
son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches

7 0
3 years ago
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