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Sergeu [11.5K]
4 years ago
7

23,793,611 around to the nearest ten thousands​

Mathematics
2 answers:
Sauron [17]4 years ago
3 0

Answer: 23,790,000

Step-by-step explanation:

V125BC [204]4 years ago
3 0
To round numbers to the nearest ten thousand, make the numbers whose last four digits are 0001 through 4999 into the next lower number that ends in 0000. For example 54,424 rounded to the nearest ten thousand would be 50,000.
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Helen's age is multiples of 4. Next year it'll be a mustiple of 3. Helen's older brother is now 19. How old is Helen now?
Firlakuza [10]

Helen is currently is 8 years old.

<h3>How to solve world problem ?</h3>

Endeavor to understand the question, analyze it and interpret it into equation.

Given that Helen's age is multiples of 4. Next year it'll be a multiple of 3. Helen's older brother is now 19.

This means Helen current age is multiple of 4 and next year it will be a multiple of 3. Also, Helen's age is less than 19

The two available numbers that fit this analysis and less than 19 are 8 and 9. 8 is multiple of 4. 8 + 1 = 9 which is multiple of 3

Therefore, Helen is 8 years old now

Learn more about Arithmetic here: brainly.com/question/6561461

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8 0
2 years ago
A study recently confirmed that of every 100 citizens of a certain​ state, 60 are considered overweight. There were 279 million
suter [353]
167 would be considered overweight
3 0
4 years ago
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Write the expression 6a - 2 (a - 1)
ehidna [41]
The answer is 4
A = 1 so, 6x1 is 6 - 2 = 4
5 0
3 years ago
Y - 5 = 0.5x2 + 6x - 3 How many x-intercepts does this have?<br> update!!! the answer is 2
diamong [38]
The answer is actually 2 because you have 0.5x (I think that's what it's supposed to be) and 6x.
5 0
3 years ago
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Factorise 3(3x-y)-(y-3x)
snow_lady [41]

Answer:

4(3x-y)

Step-by-step explanation:

Given:

\displaystyle \large{3(3x-y)-(y-3x)}

To factor this kind of expression, first, find the common factor.

\displaystyle \large{3(3x-y)-(-3x+y)}\\\displaystyle \large{3(3x-y)+(3x-y)}

Notice that in the expression, we have both same (3x-y). Therefore, (3x-y) is our factor.

Let u = 3x-y

\displaystyle \large{3u+u}\\\displaystyle \large{4u}

Change u back to 3x-y:

\displaystyle \large{4(3x-y)}

Therefore, the factored expression is 4(3x-y).

4 0
2 years ago
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