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levacccp [35]
3 years ago
8

Calculate the distance between the points J=(-3, 2) and K=(2, -2) in the coordinate plane.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

\sqrt{41}

Step-by-step explanation:

Hello!

In order to answer this question, we need to use the distance formula.

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The order of these points can be chosen in any way, but they need to be done in the same pair (just like when you find the slope).

For this problem, let's let the J pair be the x_2, y_2 pair and the K pair be the x_1,y_1 pair.

x_2 = -3

x_1 = 2

y_2 = 2

y_1 = -2

Now, let's plug these points in.

\sqrt{(-3-2)^2+(2-(-2))^2}

\sqrt{(-3-2)^2+(2+2)^2}

\sqrt{(-5)^2+(4)^2}

\sqrt{25+16}

\sqrt{41}

Thus, the distance between points (-3,2) and (2,-2) is \sqrt{41}.  

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Perform long division
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           ----------------------------------------
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