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NISA [10]
3 years ago
14

A sample of 50 observations is taken from an infinite population. The sampling distribution of : a.is approximately normal becau

se of the central limit theorem. b.cannot be determined. c.is approximately normal because is always approximately normally distributed. d.is approximately normal because the sample size is small in comparison to the population size.
Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

a.is approximately normal because of the central limit theorem.

Step-by-step explanation:

The central limit theorem states that if we have a population with mean μ and standard deviation σ and we take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

For any distribution if the number of samples n ≥ 30, the sample distribution will be approximately normal.

Since in our question, the sample of observations is 50, n = 50.

Since 50 > 30, then <u>our sample distribution will be approximately normal because of the central limit theorem.</u>

So, a is the answer.

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I need help for this multiply choice geometry problem
Misha Larkins [42]

Answer:

Answer B

Step-by-step explanation:

As we can see in the figure, AB is parallel with DE, AE and BD intersect each other at point C.

=> So that ACB and ECD are two congruent triangles.

According to the features of two congruent triangles, we have:

AC/EC =  CB/CD = AB/ED

=> 4/8 = 3/6 = AB/ ED

=> AB/ ED = 1/2

=> AB = 1/2 ED

=> AB = 1/2 x 3

=> x= 0.5

So the value of x if 1.5

Correct answer is B

5 0
3 years ago
Which list is in order from least to greatest? 1.94 x 10 1.25x 10.6x109.8.1 x 10 O 1.25x 10-2 194 10*6x10* 8.1 x 10 O 1.25x 10-2
pickupchik [31]

Answer:

(a)\ 1.94 * 10 ^{-5},\ \ 1.25 *10 ^{-2},\ \ 6 *10 ^{4},\ \ 8.1 *10^{4}

Step-by-step explanation:

Given

(a)\ 1.94 * 10 ^{-5},\ \ 1.25 *10 ^{-2},\ \ 6 *10 ^{4},\ \ 8.1 *10^{4}

(b)\ 1.94 * 10 ^{-5},\ \ 6 * 10^4, \ \ 8.1 *10^{4},\ \ 1.25 *10 ^{-2}

(c)\ 1.94 * 10 ^{-5}, \ \ 8.1 *10^{4},\ \ 6 * 10^4,\ \ 1.25 *10 ^{-2}

(d)\ 1.94 * 10 ^{-5},\ \ 1.25 *10 ^{-2},  \ \ 8.1 *10^{4},\ \ 6 * 10^4

Required

Which list is in ascending order

To do this, we analyze each of the options 1 after the other.

(a)\ 1.94 * 10 ^{-5},\ \ 1.25 *10 ^{-2},\ \ 6 *10 ^{4},\ \ 8.1 *10^{4}

Convert each list item to decimal

1.94 * 10 ^-5 = 0.0000194

1.25 *10 ^-2 = 0.0125

6 *10^{4} = 60000

8.1 *10^{4} = 81000

The list is in ascending order because:

0.0000194 < 0.0125 < 60000 < 81000

<em>No need to test other options</em>

5 0
3 years ago
I don't understand this​
drek231 [11]
Ok I will help u....

if u have any doubts ask me
please mark as brainliest
6 0
3 years ago
Read 2 more answers
Write an equivalent expression for -6(a+8)
stepan [7]
-6a-48 that would be it because you are only distributing the -6
8 0
3 years ago
The diagram shows a sector of a circle radius 10cm
Yuki888 [10]

Answer:

\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}

Step-by-step explanation:

\text{Perimeter of the sector = Radius + arc length + radius}

\text{Radius = 10 cm}

\text{Perimeter of the sector = 10 + arc length + 10  }

 \text{Perimeter of the sector = 20 + arc length  }

\text{arc length   = (sector angle/ 360 ) * perimeter of the circle}

\text{Perimeter of a circle }=2\pi r

\text{sector angle} = 135

\text{arc length}   =  (135/ 360 ) * 2\pi (10)

= (3/8) 20\pi

= 15\pi /2

\text{Using  }\pi =3.14

= 15 * 3.14 /2

= 23.55

\text{Perimeter of the sector = 20  + 23.55}

= 43.55

= 43.6  cm

\text{perimeter of the sector  = 43.6  cm }

8 0
2 years ago
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