Answer:
Adding moisture to the waste in a suitably designed and operated landfill should increase its degradation, leading to less risk and a move towards sustainability. ... Proper aeration, moisture addition and gas extraction are needed to control the environment required for aerobic processes to thrive with optimum efficiency.
Explanation:
Answer:
While the long-billed prairie-bird’s fundamental niche included a wide range of prey species, competition with other species in the newly colonized prairie reduced the realized niche such that fewer food types were utilized
Explanation:
Options are given:
The two populations of the long-billed prairie-birds had different fundamental niches, but the same realized niche
The original population of long-billed prairie-birds had higher levels of competition for food resources and in order to find enough food had a more varied diet. Those in the newly colonized area faced less competition and adapted to a smaller range of food types.
While the long-billed prairie-bird’s fundamental niche included a wide range of prey species, competition with other species in the newly colonized prairie reduced the realized niche such that fewer food types were utilized
The long-billed prairie-bird’s fundamental niche shifted as a result of competition with other species such that individuals in the newly colonized prairie foraged on a smaller variety of food types
Since in the question it is mentioned that scientists compare the populations with respect to the two bird and determined for the long billed prairie birds and the available of food is same in the two areas
This above situation represents the competitive exclusion concept. The species should be entered into the competitor in the case when there is a large number and the feeding should be started for survival
Answer:
The frequency of the recessive allele. Answer: Since we believe that the homozygous recessive for this gene (q2) represents 4% (i.e. = 0.04), the square root (q) is 0.2 (20%).
The frequency of the dominant allele. Answer: Since q = 0.2, and p + q = 1, then p = 0.8 (80%).
The frequency of heterozygous individuals.
Explanation:
