Sample space ={1,2,3,4,5,6}
P(one "6) = 1/6
Q(NOT getting any "6) = 5/6
⁴C₂(P)²(Q)² = ⁴C₂(1/6)²(5/6)² = ⁴C²(25/1296)
⁴C₂ = (4!)/(2!)(2!) = 6
Then Probability(getting 2 "6" in 4 rolls) = 6(25/1296) = 25/216 = 0.1157
Total area of the poster = 26^2 = 676 square inches
area of 1 triangle = 1/2 x 8 x 8 = 32 square inches
area of the 4 triangles = 32 *4 = 128 square inches
probability of getting the dart in a triangle = 128 / 676 = 0.189
rounded to nearest hundredth = 0.19
Answer:
None of the above, the correct answer is 2.2
Step-by-step explanation:
6.4
4.2
----
2.2
Part C:
Assume $x is what Laura's earn in one hour.
Jess earns in one hour is: j = $x - $2.90
Part D:
Jess earns in 20 hours:
20 * ($x - $2.90) = $20x - $58 (I.e. Jess earns $58 less than Laura)
Is the third side the hypotenuse?
