Answer:
JK got 30 answers correct on a 50 item test.
Step-by-step explanation:
It is given that:
Total items on test = T = 50
Fraction of total items that were answered correctly = 3/5
We simply have to multiply the total number of questions by the fraction of correct answers.
So,
The correct answered number of items are:

Hence,
JK got 30 answers correct on a 50 item test.
Answer:
Cos 74°= Sin 16°
Sin 20°= Cos 70°
Sin A°=Cos (90°- A°)
Step-by-step explanation:
This is because the three pairs are complementary i.e they add up to 90° and in trigonometric ratios, complementary ratios are equal.
what is your clear question? it lacks some details
Answer:
The third one, x+(x+1)+(x+2)=-21 because x, x+1 and x+2 are three consecutive numbers.
Answer:
24761 mosquitoes
5.4 days
Step-by-step explanation:
Let the equation that shows the population of the mosquitoes after x days,

Where,
P = Initial population,
r = rate of increasing per day,
Here, A = 1000, when x = 0,

A = 1900 when x = 1,

Thus, the required function that represents the population after x days,

If x = 4,
The number of mosquito after 4 days,

If A = 60,000,


Taking log both sides,


Thus, there will 60,000 mosquitoes after 5 days.