Answer:
2
Step-by-step explanation:
Answer: the answer is d
Step-by-step explanation: if the sign is like this > the arrow moves to the right and if its like < its to the left.
if the circle on the 11 is bold that means theres a line under > if theres no bold that means there's no line under the >.
the line means less than or equal too
goodluck :)
Μ = (0×0.026) + (1×0.072) +(2×0.152) + (3×0.303) + (4×0.215) + (5×0.164) + (6×0.066)
μ = 0 + 0.072 + 0.304 + 0.909 + 0.86 + 0.82 + 0.396
μ = 3.361 ≈ 3.4
We need the value of ∑X² to work out the variance
∑X² = (0²×0.026) + (1²×0.072) + (2²×0.152) + (3²×0.303) + (4²×0.215) + (5²×0.164) + (6²×0.066)
∑X² = 0+0.072+0.608+2.727+3.44+4.1+2.376
∑X² = 13.323
Variance = ∑X² - μ²
Variance = 13.323 - (3.4)² = 1.763 ≈ 2
Standard Deviation = √Variance = √1.8 = 1.3416... ≈ 1.4
The correct answer related to the value of mean and standard deviation is the option D
<span>
An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.4 hours.</span>
It is usual to represent ratios in their simplest form so that we are not operating with large numbers. Reducing ratios to their simplest form is directly linked to equivalent fractions.
For example: On a farm there are 4 Bulls and 200 Cows. Write this as a ratio in its simplest form.
Bulls <span>: </span>Cows
4 <span>: </span>200
If we halve the number of bulls then we must halve the number of cows so that the relationship between the bulls and cows stays constant. This gives us:
Bulls <span>: </span>Cows
2 <span>: </span>100
Halving again gives us
1 <span>: </span>50
So the ratio of Bulls to Cows equals 1 : 50. The ratio is now represented in its simplest form.
An example where we have 3 quantities.
On the farm there are 24 ducks, 36 geese and 48 hens.
Ratio of ducks <span>: </span>geese <span>: </span>hens
24 <span>: </span>36 <span>: </span>48
Dividing each quantity by 12 gives us
2 <span>: </span>3 : 4
So the ratio of ducks to geese to hens equals 2 : 3 : 4 which is the simplest form since we can find no further common factor.
