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liberstina [14]
3 years ago
12

Which expression is equivalent to ? Assume

Mathematics
2 answers:
stepan [7]3 years ago
7 0

Answer:

b/a

Step-by-step explanation:

Given,(b^-2)/a*(b^-3)

or,(b^-2+3)/a

or,b/a

tatiyna3 years ago
5 0

Answer:

b/a

Step-by-step explanation:

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Write an equation in slope-intercept form for the line with slope -2 and y-intercept 5.
Nana76 [90]

Answer:

y = -2x + 5

Step-by-step explanation:

5 0
3 years ago
|x|+5=18 a. 5 or -5 b.13 or -13 c.18 or -18 d.23 -23
dezoksy [38]
X+5=18
first get rid of the 5
so X+5-5=18-5
which makes X=13
if any questions please ask
b. 13
6 0
3 years ago
In triangle ABC, angle C is a right angle and BC=5. If measure of angle B = 30 degrees, find AC
Nina [5.8K]
Answer = d

using the 30 - 60 - 90 triangle theorem

side across from the angle

across from angle 30 is x
across from angle 60 is x rad. 3
across from 90 is 2x

BC is across from angle 60
so BC is the x rad 3
set the given measurement equal to it

x sqrt 3 = 5
÷ sqrt 3 ÷ sqrt 3
x = (5/ sqrt 3)
multiply top and bottom by the radical to get rid of the radical in the bottom

x = (5/ sqrt 3) × (sqrt 3/sqrt 3)
x = 5 sqrt 3/ 3

since side BC is x
BC = 5 sqrt 3/ 3

* Drawing the triangle diagram would help*
5 0
3 years ago
Read 2 more answers
Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)
Paladinen [302]

Step-by-step explanation:

Let x represent theta.

\sin( \frac{\pi}{4} - x )

Using the angle addition trig formula,

\sin(x - y)  =  \sin(x)  \cos(y)  -  \cos(x)  \sin(y)

\sin( \frac{\pi}{4} )  \cos(x)  -  \cos( \frac{\pi}{4} )  \sin(x)

( \frac{ \sqrt{2} }{2})  \cos(x)  -  (\frac{ \sqrt{2} }{2}  )\sin(x)

Multiply one side at a time

Replace theta with x , the answer is

\frac{ \sqrt{2} \cos(x)  }{2}  -  \frac{ \sin(x) \sqrt{2}  }{2}

2. Convert 30 degrees into radian

\frac{30}{1}  \times  \frac{\pi}{180}  =  \frac{\pi}{6}

Using tangent formula,

\tan(x + y)  =  \frac{ \tan(x)  +  \tan(y) }{1 -  \tan(x) \tan(y)  }

\frac{ \tan(x) +  \tan( \frac{\pi}{6} )  }{1 -  \tan(x) \tan( \frac{\pi}{6} )  }

Tan if pi/6 is sqr root of 3/3

\frac{ \tan(x) +  ( \frac{ \sqrt{3} }{3} )  }{1 -  \tan(x)  (\frac{ \sqrt{3} }{3} )  }

Since my phone about to die if you later simplify that,

you'll get

\frac{(3 \tan(x) +  \sqrt{3} )(3 +  \sqrt{3}  \tan(x)  }{3(3 -  \tan {}^{2} (x) }

Replace theta with X.

4 0
2 years ago
How many bases are there in the triangular pyramid shown below?
sukhopar [10]

Answer:

1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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