Answer:
a
Step-by-step explanation:
i passed grade 6 lol
Answer:
Step-by-step explanation:
Problem One
All quadrilaterals have angles that add up to 360 degrees.
Tangents touch the circle in such a way that the radius and the tangent form a right angle at the point of contact.
Solution
x + 115 + 90 + 90 = 360
x + 295 = 360
x + 295 - 295 = 360 - 295
x = 65
Problem Two
From the previous problem, you know that where the 6 and 8 meet is a right angle.
Therefore you can use a^2 + b^2 = c^2
a = 6
b =8
c = ?
6^2 + 8^2 = c^2
c^2 = 36 + 64
c^2 = 100
sqrt(c^2) = sqrt(100)
c = 10
x = 10
Problem 3
No guarantees on this one. I'm not sure how the diagram is set up. I take the 4 to be the length from the bottom of the line marked 10 to the intersect point of the tangent with the circle.
That means that the measurement left is 10 - 4 = 6
x and 6 are both tangents from the upper point of the line marked 10.
Therefore x = 6
For this, all you'll wanna do is add the answer to this problem to your original number...
16× .75 = 12
now add...
16 + 12 = 28$ per pound...
to make a 75% profit on the markets investment....I think I'll have a salad instead at that price...
Answer:
23.7 be the answer
Step-by-step explanation:
23.68 look to the 8 if it 5 or more round next door
4 or less kill the rest
