Answer:
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Answer:
int ComputeFibonacci(int N) {
if(N == 0)
return 0;
else if (N == 1)
return 1;
else
return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);
}
Explanation:
Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.
For example,
If N = 4 as in the main part:
ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3
ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2
ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0 = 1
*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.
In this activity Morgan is preparing the digital files to a printer on a DTP project.
Explanation:
DTP project is the creation of documents using page layout on a personal computer. The process of printing digital based images directly to variety of media substrates is known as digital processing.
The digital files like PDFs can be sent directly to digital printing press to print on paper, photo paper, fabric and so on.
They have unique fade rates and different sensitives to the various deterioration mechanisms. DTP is used for graphic designers to create documents.
It would be b 48 for the correct answer
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