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rusak2 [61]
3 years ago
9

What did I do wrong? May you please correct it for me...I was also looking on how to delay when it prints. Like when it prints a

sentence I want it to wait about 2 seconds.
Here's the code:

print("\nWelcome to the impossible quiz!\n")

name = input("What's your name before we get started? ")

print("Nice to meet you, "+ name)

print("\nThe rules are very simple, get the answer right and you get 10 points. You only have one chance to get the answer right, get it wrong and you'll lose 3 points! ")

input("\nReady?\n")

user_score = 0

print("First question: Do slugs have four noses?")
if answer = input('Give "F" for False or "T" for True: ')

if answer == "T":
print("Correct, you've gained 10 points!")
user_score += 10

elif answer == "F":
print("Incorrect, you've lost 3 points!")
user_score += -3

Computers and Technology
1 answer:
inessss [21]3 years ago
4 0

Answer:

print("\nWelcome to the impossible quiz!\n")

name = input("What's your name before we get started? ")

print("Nice to meet you, "+ name)

print("\nThe rules are very simple, get the answer right and you get 10 points. You only have one chance to get the answer right, get it wrong and you'll lose 3 points! ")

input("\nReady?\n")

user_score = 0

print("First question: Do slugs have four noses?")

answer = input('Give "F" for False or "T" for True: ')

if answer == "T":

time.sleep(2)

print("Correct, you've gained 10 points!")

user_score += 10

elif answer == "F":

time.sleep(2)

print("Incorrect, you've lost 3 points!")

user_score += -3

Explanation:

Please check the answer. However, if before answer was wrong, and we need to use time.sleep(2) for delaying printing.

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Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value o
Fantom [35]

Complete question:

Scrabble is a word game in which words are constructed from letter tiles, each letter tile containing a point value. The value of a word is the sum of each tile's points added to any points provided by the word's placement on the game board. Write a program using the given dictionary of letters and point values that takes a word as input and outputs the base total value of the word (before being put onto a board). Ex:  If the input is:  PYTHON

the output is: 14

part of the code:

tile_dict = { 'A': 1, 'B': 3, 'C': 3, 'D': 2, 'E': 1, 'F': 4, 'G': 2, 'H': 4, 'I': 1, 'J': 8,  'K': 5, 'L': 1, 'M': 3, 'N': 1, 'O': 1, 'P': 3, 'Q': 10, 'R': 1, 'S': 1, 'T': 1,  'U': 1, 'V': 4, 'W': 4, 'X': 8, 'Y': 4, 'Z': 10 }

Answer:

Complete the program as thus:

word = input("Word: ").upper()

points = 0

for i in range(len(word)):

   for key, value in tile_dict.items():

       if key == word[i]:

           points+=value

           break

print("Points: "+str(points))

Explanation:

This gets input from the user in capital letters

word = input("Word: ").upper()

This initializes the number of points to 0

points = 0

This iterates through the letters of the input word

for i in range(len(word)):

For every letter, this iterates through the dictionary

   for key, value in tile_dict.items():

This locates each letters

       if key == word[i]:

This adds the point

           points+=value

The inner loop is exited

           break

This prints the total points

print("Points: "+str(points))

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3 years ago
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