Answer:
Step-by-step explanation:
1) (i) HG ≅ ST ; GI ≅ TR ; IH ≅ RS
ΔHGI ≅ ΔSTR by S S S congruent
(ii) ∠H ≅ ∠S ; HG ≅ ST ; ∠G ≅ ∠T
ΔHGI ≅ ΔSTR by A S A -> Angle Side Angle congruent.
3) LM ≅ XY ; MK ≅ YZ ; KL ≅ ZX
ΔLMK ≅ ΔXYZ Side Side Side congruent
∠K ≅ ∠Z ; KL ≅ ZX ; ∠L ≅ ∠X
ΔLMK ≅ ΔXYZ by Angle Side Angle congruent
The base is 3+(x), altitude is x so substitute. Now we know the area of a triangle is base X height X 1/2. Substitute again! 1/2 (3+x)(x)=35. Multiply both sides by 2 to cancel out the 1/2. Now you have (x)(x+3)=70 and you have to foil out the left side x^2+3x=70. Subtract 70 on both sides x^2+3x-70=0. Find two numbers that multiply to -70 and add to 3. Solve (x+10)(x-7)=0. the x value is 7. since you can't have negative length values. Substitute 7 into 3+x for the base so you know the base is 10 and the height is 7.
They are circle and triangle.
Best of luck in geometry
Answer:
Step-by-step explanation:
Straight line is an angle whose vertex point(O) has a value of 180. The arms (OA & OB) of the straight line angle lies opposite to each other from the vertex point
Sum of all the angles in a straight line = 180
From this you can find the value of unknown angle, if other angles are given.
∠AOC + ∠BOC = 180
