ACE IS THE CORRECT ANSWER
This is because
The triangle a c and e
<h2>Explanation:</h2><h2 />
- The input of a function is also called the domain and are those x-values for which the function is defined.
- The output of a function is also called the range and are those y-values for which the function is defined.
Here we have the following function:
![y=f(x)=sin(x)](https://tex.z-dn.net/?f=y%3Df%28x%29%3Dsin%28x%29)
And we know that:
Input:
![\boxed{x=60^{\circ}}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D60%5E%7B%5Ccirc%7D%7D)
Output:
![y=sin(60^{\circ}) \\ \\ \therefore \boxed{y=\frac{\sqrt{3}}{{2}}}](https://tex.z-dn.net/?f=y%3Dsin%2860%5E%7B%5Ccirc%7D%29%20%5C%5C%20%5C%5C%20%5Ctherefore%20%5Cboxed%7By%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B%7B2%7D%7D%7D)
Answer:
A). F = ![\frac{9C}{5}+32](https://tex.z-dn.net/?f=%5Cfrac%7B9C%7D%7B5%7D%2B32)
B). 374°F
Step-by-step explanation:
A). Formula to convert the temperature from degree centigrade to °F is,
C = ![\frac{5}{9}(F-32)](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%28F-32%29)
We have to solve the formula to get the value of F,
9 × C = ![9\times \frac{5}{9}(F-32)](https://tex.z-dn.net/?f=9%5Ctimes%20%5Cfrac%7B5%7D%7B9%7D%28F-32%29)
9C = 5(F - 32)
![\frac{9C}{5}=\frac{5(F-32)}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B9C%7D%7B5%7D%3D%5Cfrac%7B5%28F-32%29%7D%7B5%7D)
![\frac{9C}{5}=(F-32)](https://tex.z-dn.net/?f=%5Cfrac%7B9C%7D%7B5%7D%3D%28F-32%29)
F = ![\frac{9C}{5}+32](https://tex.z-dn.net/?f=%5Cfrac%7B9C%7D%7B5%7D%2B32)
B). In this part we have to find the value of 190° C in °F.
From the formula given in part (A),
F = ![\frac{9\times 190}{5}+32](https://tex.z-dn.net/?f=%5Cfrac%7B9%5Ctimes%20190%7D%7B5%7D%2B32)
= 374°
Therefore, 190°C = 374°F
The area of a trapezoid is basically the average width times the altitude, or as a formula:
Area = h ·
b 1 + b 2
2
where
b1, b2 are the lengths of each base
h is the altitude (height)
Recall that the bases are the two parallel sides of the trapezoid. The altitude (or height) of a trapezoid is the perpendicular distance between the two bases.
In the applet above, click on "freeze dimensions". As you drag any vertex, you will see that the trapezoid redraws itself keeping the height and bases constant. Notice how the area does not change in the displayed formula. The area depends only on the height and base lengths, so as you can see, there are many trapezoids with a given set of dimensions which all have the same area.