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aleksandr82 [10.1K]
3 years ago
11

Which is the value of Y in the parallelogram below?

Mathematics
1 answer:
IrinaK [193]3 years ago
4 0

Answer:

9

Step-by-step explanation:

Just like a rectangle, times one length times width

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How many times does 20 go into 100
ss7ja [257]

Answer:

5 times

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Write (y^2)^3 without exponents, and fill in the blank​
irinina [24]

Answer:

y*y*y*y*y*y

Step-by-step explanation:

(y^{2})^{3} = y^{6} = y*y*y*y*y*y

7 0
3 years ago
Given that u =< 2,12 >, and z =< -7,5 >
swat32

Using the dot product:

For any vector x, we have

||x|| = √(x • x)

This means that

||w|| = √(w • w)

… = √((u + z) • (u + z))

… = √((u • u) + (u • z) + (z • u) + (z • z))

… = √(||u||² + 2 (u • z) + ||z||²)

We have

u = ⟨2, 12⟩   ⇒   ||u|| = √(2² + 12²) = 2√37

z = ⟨-7, 5⟩   ⇒   ||z|| = √((-7)² + 5²) = √74

u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46

and so

||w|| = √((2√37)² + 2•46 + (√74)²)

… = √(4•37 + 2•46 + 74)

… = √314 ≈ 17.720

Alternatively, without mentioning the dot product,

w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩

and so

||w|| = √((-5)² + 17²) = √314 ≈ 17.720

7 0
2 years ago
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
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Write the equation of the line that passes through the points (-4,8) and (-2, -1).
IRINA_888 [86]

Answer:

y=-9/2x-10

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-8)/(-2-(-4))

m=-9/(-2+4)

m=-9/2

y-y1=m(x-x1)

y-8=-9/2(x-(-4))

y-8=-9/2(x+4)

y=-9/2x-36/2+8

y=-9/2x-18+8

y=-9/2x-10

5 0
3 years ago
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