Question

If (x) = x / x^2-16 what is the value of f(-10)

Answer 1

Answer:

$f(-10)=-\dfrac{5}{42}$

Step-by-step explanation:

You just replace 'x' for the value given, -10.

$f(x)=\dfrac{x}{x^2-16}\\\\\\f(-10)=\dfrac{-10}{(-10)^2-16}=\dfrac{-10}{100-16}=\dfrac{-10}{84}\\\\\\\\\\f(-10)=-\dfrac{5}{42}$