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kipiarov [429]
3 years ago
13

If (x) = x / x^2-16 what is the value of f(-10)

Mathematics
1 answer:
Yuliya22 [10]3 years ago
5 0

Answer:

f(-10)=-\dfrac{5}{42}

Step-by-step explanation:

You just replace 'x' for the value given, -10.

f(x)=\dfrac{x}{x^2-16}\\\\\\f(-10)=\dfrac{-10}{(-10)^2-16}=\dfrac{-10}{100-16}=\dfrac{-10}{84}\\\\\\\\\\f(-10)=-\dfrac{5}{42}

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Read 2 more answers
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