3 years ago

If (x) = x / x^2-16 what is the value of f(-10)

Mathematics

1 answer:

Yuliya22 [10]3 years ago

5 0

Answer:

$f(-10)=-\dfrac{5}{42}$

Step-by-step explanation:

You just replace 'x' for the value given, -10.

$f(x)=\dfrac{x}{x^2-16}\\\\\\f(-10)=\dfrac{-10}{(-10)^2-16}=\dfrac{-10}{100-16}=\dfrac{-10}{84}\\\\\\\\\\f(-10)=-\dfrac{5}{42}$

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