Question

If 8a + 3b + 2c = 3, what is 64a+24b+16c?

Answer 1

Answer:

64a+24b+16c = 24

Step-by-step explanation:

Given :  8a + 3b + 2c = 3

We have to find the value of 64a+24b+16c

Consider 64a+24b+16c

Taking 8 common from each term , we have,

64a+24b+16c = 8(8a + 3b + 2c)

Also, given  8a + 3b + 2c = 3

Then , 64a+24b+16c = 8(8a + 3b + 2c)

= 8(3)

Simplify , we have,

= 24

Thus, 64a+24b+16c = 24

Answer 2

The second expression is 8 times the first so the answer is 3 * 8 = 24.