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4 years ago

If 8a + 3b + 2c = 3, what is 64a+24b+16c?

Mathematics

2 answers:

Dmitrij [34]4 years ago

5 0

Answer:

64a+24b+16c = 24

Step-by-step explanation:

Given : 8a + 3b + 2c = 3

We have to find the value of 64a+24b+16c

Consider 64a+24b+16c

Taking 8 common from each term , we have,

64a+24b+16c = 8(8a + 3b + 2c)

Also, given 8a + 3b + 2c = 3

Then , 64a+24b+16c = 8(8a + 3b + 2c)

= 8(3)

Simplify , we have,

= 24

Thus, 64a+24b+16c = 24

algol [13]4 years ago

3 0

The second expression is 8 times the first so the answer is 3 * 8 = 24.

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