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jeyben [28]
3 years ago
15

If 8a + 3b + 2c = 3, what is 64a+24b+16c?

Mathematics
2 answers:
Dmitrij [34]3 years ago
5 0

Answer:

64a+24b+16c = 24

Step-by-step explanation:

Given :  8a + 3b + 2c = 3

We have to find the value of 64a+24b+16c

Consider 64a+24b+16c

Taking 8 common from each term , we have,

64a+24b+16c = 8(8a + 3b + 2c)

Also, given  8a + 3b + 2c = 3

Then , 64a+24b+16c = 8(8a + 3b + 2c)

= 8(3)

Simplify , we have,

= 24

Thus, 64a+24b+16c = 24

algol [13]3 years ago
3 0
The second expression is 8 times the first so the answer is 3 * 8 = 24.
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