Answer:
158
Step-by-step explanation:
Rational exponents
![a^\frac{m}{n}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bm%7D%7Bn%7D)
work like this: the numerator is the actual exponent of the base, while the denominator is the index of the root.
In other words, we have
![a^\frac{m}{n}=\sqrt[n]{a^m}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D)
So, in you case, we have
![\sqrt[5]{x^3}=x^\frac{3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%3Dx%5E%5Cfrac%7B3%7D%7B5%7D)
Assuming that the question contanis a typo. If you actually mean
,
then you can write it as ![5x^\frac{1}{3}](https://tex.z-dn.net/?f=5x%5E%5Cfrac%7B1%7D%7B3%7D)
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.
<span>First find the area of the field
A=WL
A=(110m)(60m)
A=6,600m^2
Now turn the cm into m
becouse 100cm^3=1m^3
660,000,000cm^3=6,600,000m^3
Now find out how many times you can cover the filled
6,600,000m^3/6,600m^2=100m
So it will be 100m thick.
P.S. I'm assuming you meant you jest forgot the m for 110m.</span>