<u>Given:</u>
Polynomial = P(x) = 3x² + kx + 6
Factor of the ablove polynomial = (x+3)
<u>To </u><u>Find</u><u>:</u>
Value of K, for which (x+3) become the factor of P(x) = 3x² + kx + 6
<u>Solu</u><u>tion</u><u> </u><u>:</u>
Now,
x + 3 = 0
⇒x = (-3)
So,
As (x+3) is a factor so x = (-3) is one root of the polynomial.
Therefore,
P(-3) = 0
→ P(-3) = 3(-3)² + k(-3) + 6 = 0
→ 3(9) - 3k + 6 = 0
→ 27 - 3k + 6 = 0
→ 27 + 6 - 3k = 0
→ 33 - 3k = 0
→ - 3k = -33
→ k = -33 ÷ -3
→ k = 11
- <u>Hence,For the value of k = 11, (x+3) is a factor of 3x²+ kx + 6</u>
<h2><u>V</u><u> </u><u>E</u><u> </u><u>R</u><u> </u><u>I</u><u> </u><u>F</u><u> </u><u>I</u><u> </u><u>C</u><u> </u><u>A</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h2>
3x²+ kx + 6, by putting the value of k = 11 and taking -3 as root the remainder should be zero
→ 3x²+ 11x + 6
→ 3(-3)² + 11(-3) + 6
→ 3(9) - 33 + 6
→ 27 - 33 + 6
→ 27 + 6 - 33
→ 33 - 33
→ 0
<u>Hence verified</u><u> </u><u>!</u>
XY>XA
<span>XA ≡ YA
XP ≡ PY</span>
Then, the first statement XA ≡ XY is false
Answer:
The only difference is: If you multiply or divide both sides of an equation by the same negative number, the equation remains the same, but If you multiply or divide both sides of an inequality by the same negative number, the inequality reverses. !!!!!
Step-by-step explanation:
Answer:
idk bro but ily
Step-by-step explanation: