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2 years ago

11

ہے Solve for k. 4k - 10 k k= - = 8

1 answer:

kifflom [539]2 years ago

6 0

Answer:

The formation of the equation is odd, but I assume it's supposed to be:
4k - 10k = -8k

-6k = -8k
-6k + 8k = -8k + 8k
2k = 0
$\frac{2k}{2}$ = $\frac{0}{2}$
k = 0

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Answer:

58

Step-by-step explanation:

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3 years ago

Use the quadratic formula to solve the equation: 0 = x2 + x - 20

Art [367]

Answer:

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Step-by-step explanation:

a= 1

b= 1

c= -20

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4 years ago

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4 years ago

Given: circle k(O), m LM = 164°, m WK = 68°, m∠MLK = 65°. Find: m∠LMW

Musya8 [376]

Answer:

The measure of angle LMW is $m\angle LMW=67\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of arc MW

we know that

The inscribed angle measures half that of the arc comprising

so

$m\angle MLK=\frac{1}{2}[arc\ MW+arc\ WK]$

substitute the given values

$65\°=\frac{1}{2}[arc\ MW+68\°]$

$130\°=[arc\ MW+68\°]$

$arc\ MW=130\°-68\°=62\°$

step 2

Find the measure of arc LK

we know that

$arc\ LM+arc\ MW+arc\ WK+arc\ LK=360\°$ -----> by complete circle

substitute the given values

$164\°+62\°+68\°+arc\ LK=360\°$

$294\°+arc\ LK=360\°$

$arc\ LK=360\°-294\°=66\°$

step 3

Find the measure of angle LMW

we know that

The inscribed angle measures half that of the arc comprising

so

$m\angle LMW=\frac{1}{2}[arc\ LK+arc\ WK]$

substitute the given values

$m\angle LMW=\frac{1}{2}[66\°+68\°]=67\°$

4 0

3 years ago

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xxTIMURxx [149]

Answer:

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2

hope it helps

7 0

3 years ago

Read 2 more answers