Complete question:
Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?
Answer:
Here,
Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)
We are also told only 10 participants are available.
All 10 participants are being exposed to all five levels of the color variable in the same order.
Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.
Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.
But using counterbalancing technique, Dr. Lyte can avoid such an error.
Answer:
#3
Step-by-step explanation:
The inequality is 
because we start off with 95 pounds and then add on x more (x is some positive number). The expression 95+x is the total weight. We want this total weight to be less than or equal to 800. In other words, 800 is the highest we can go. Or put another way, we can have 800 or smaller.
To solve that inequality, subtract 95 from both sides and you end up with this inequality 
meaning that we can add up to 705 pounds of extra people or things to this elevator.
Answer:
Step-by-step explanation:
The formula for the volume of a cylinder is V = πr²h.
Here, r = 5cm, and h = 15 cm, and so the volume is:
V = πr²h = π(5 cm)²(15 cm), or:
V = π(25 cm²)(15 cm) = 375π cm³, or approximately 1170 cm³
