Answer:
52/79
Step-by-step explanation:
One costume = 156 (This is our numerator.)
All visitors = 156 + 58 + 23 = 237 (This is our denominator.)
156/237
Find the GCF to simplify (sneak peek it's 3)
156/3 = 52
237/3 = 79
52/79 (tada!)
Answer:
380ft
Step-by-step explanation:
Assuming the balloon rises 525ft from sea level (0ft), all we need to do is subtract both numbers to find the new height.
525 - 145 = 380ft
There could be many different scenarios though because if the question provides the height of land off sea level, you would have to take that into account as well.
Best of Luck!
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
<em>Set the function equal to 0</em>
Step-by-step explanation:
<u>Standard Form of the Quadratic Equation</u>
The form
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
is called the standard form of a quadratic equation. It can be clearly identified the terms of a second-degree polynomial equated to 0.
The equation is given in the form:
![2(x-4)^2-3=8](https://tex.z-dn.net/?f=2%28x-4%29%5E2-3%3D8)
And we need to operate the expression to make it look like a standard form. The first logical step should be to set the function equal to 0 and then start to operate the resulting expression. It can be done by subtracting 8 on both sides of the equation:
![2(x-4)^2-3-8=0](https://tex.z-dn.net/?f=2%28x-4%29%5E2-3-8%3D0)
Answer: Set the function equal to 0