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3 years ago

Name the intersection of plane QMW and plane RMW

Mathematics

2 answers:

melomori [17]3 years ago

7 0

Answer:

The planes intersect at C, MW.

Norma-Jean [14]3 years ago

6 0

The answer is "C", "MW".

In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.

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A perfume company claims that the mean weight of ther new perfume is at least 8.9 fluid oz. Express the null hypothesis and the

zlopas [31]

Answer:

$H0: mu = 8.9 fl oz.\\\\$

$Ha: mu ≠8.9 fluid oz$

Step-by-step explanation:

Given that A perfume company claims that the mean weight of ther new perfume is at least 8.9 fluid oz

For testing this claim, in Statistics we perform a certain measures called hypothesis testing.

For this first step is to create null and alternate hypothesis.

Normally null hypothesis would have some statistic = something

Here we want to test the mean weight of perfume

Hence null hypothesis would be

H0: mu = 8.9 fl oz.

Alternate hypothesis would be opposite of this claim

i.e.

Ha: mu ≠8.9 fluid oz

Hence answer is

$H0: mu = 8.9 fl oz.\\\\$

$Ha: mu ≠8.9 fluid oz$

6 0

3 years ago

In the diagram below, is an altitude of DEF. What is the length of ? If necessary, round your answer to two decimal places.

padilas [110]

I hope this helps you

5 0

3 years ago

I need help on these question ASAP!!!! This is Urgent

GarryVolchara [31]

Part 1: The equation of the line is $y=2x+1$

Part 2: The equation of the line in slope intercept form is $y=-3x-1$

Explanation:

Part 1: It is given that the point A is $(1,3)$ and the line B is $y=2 x-2$

To determine the line passing through the point A and parallel to line B, let us first determine the slope and y-intercept.

From the equation of line B, the slope is $m=2$

Substituting the point $(1,3)$ and $m=2$ in slope intercept form $y=mx+b$ , we have,

$3=2(1)+b$

$3=2+b$

$1=b$

Thus, the y-intercept is $b=1$

Let us substitute the values $m=2$ and $b=1$ in the slope intercept form $y=mx+b$ , we get,

$y=2x+1$

Thus, the equation of the line passing though point A and parallel to line B is $y=2x+1$

Part 2: The given two coordinates are $(-1,2)$ and $(1,-4)$

To determine the equation of line in slope intercept form, first we shall find the slope and y-intercept.

From the graph, we can see that the line touches the y-axis at -1.

Hence, the y-intercept is $b=-1$

The formula for slope is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting the coordinates $(-1,2)$ and $(1,-4)$ , we have,

$m=\frac{-4-2}{1+1} =\frac{-6}{2} =-3$

Thus, the slope is $m=-3$

Substituting the values $b=-1$ and $m=-3$ in the slope intercept formula $y=mx+b$ , we get,

$y=-3x-1$

Thus, the equation of the line in slope intercept form is $y=-3x-1$

4 0

3 years ago

Help please due today

Deffense [45]

The answer is 2 I believe

5 0

3 years ago

how do I figure out the weight loss of tina? she lost 3 pounds on the first week of her diet. she gained a pound on the second w

hram777 [196]

1st week - Lost 3 pounds = +3
2nd week - Gained 1 pound = -1
3+13 = + 22

So 22+3 = 25 25-1 = 24

So Tina lost 24 pounds in 13 weeks.

8 0

3 years ago