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3 years ago

Name the intersection of plane QMW and plane RMW

Mathematics

2 answers:

melomori [17]3 years ago

7 0

Answer:

The planes intersect at C, MW.

Norma-Jean [14]3 years ago

6 0

The answer is "C", "MW".

In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.

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Make x the subject of m=n + x/p

marshall27 [118]

Answer:

$\boxed{x = p(m - n)}$

Step-by-step explanation:

$= > m = n + \frac{x}{p} \\ \\ = > m = (n \times \frac{p}{p} ) + \frac{x}{p} \\ \\ = > m = \frac{pn}{p} + \frac{x}{p} \\ \\ = > m = \frac{pn + x}{p} \\ \\ = > mp = pn + x \\ \\ = > x + pn = pm \\ \\ = > x = pm - pn \\ \\ = > x = p(m - n)$

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3 years ago

The surface area of the prism is ______ square units. All measurements in the image below are in units. (Input the whole number

zmey [24]

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3 years ago

If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a

kolbaska11 [484]

Answer:

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

8s-6 = 2s + 22+ ∠EBF

∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

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3 years ago

What is the radius of a circle in which a 30 degrees arc is 2 inches long

igomit [66]

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12/pi =r

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3 years ago

Pleasee! Which expression is equivalent to the given expression? Assume the denominator does not equal zero.

Ilia_Sergeevich [38]

Answer:

A. 2y^4 over x^2

Step-by-step explanation:

4x^4y^6 ÷ 7x^8y^2

First, you will find the GCF of the equation which is: 7x^4y^2 .

Then, you will divide both of the equation by the GCF which will become:

14x^4y^6 ÷ 7x^4y^2 = 2y^4

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Hence, the final answer is 2y^4 over x^2

6 0

3 years ago

Read 2 more answers