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Maru [420]
2 years ago
14

The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the

smaller number ?
×-(×+4)=52
×+(×+4)=52
×(×+4)=52
×(×-4)=52​
Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
6 0

Answer:Let's assume x be the smaller number.

Given that, The greater number is 4 more than the smaller number.

So, greater number= x+4.

It's also given that, The sum of two numbers is 52. Which means sum of x and x+4 must be equa to 52. Hence,

x + (x + 4) = 52

Step-by-step explanation:

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Write a formula for function f in terms of function g.
emmasim [6.3K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


so hmm if you notice, your f(x) there, looks just like g(x), but is "shifted horizontally" by about 9 units to the right

that simply means, based on that template above, that C/B = -9, and we can simply make B = 1  and C = -9, and we get C/B = -9/1 which is -9

thus   \bf \begin{array}{llcll}
f(x)=g(&1x&-9)\\
&\uparrow &\uparrow \\
&B&C
\end{array}\iff f(x)=g(x-9)
7 0
3 years ago
If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function". C = {(9, 1
Deffense [45]

Answer:

A: Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3}

Step-by-step explanation:

C = {(9, 1) (8, -3) (7, 5) (-5, 3)}

The domain is the inputs

Domain: { -5,7,8,9}

The range is the output

Range{ -3,1,3,5}

This is a functions since there is no input that goes to multiple outputs

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sergiy2304 [10]
Translate the equation to math.
It says the term after the current term is the current term plus 3.
Next term = this term + 3
Next term = -4+3
The next term is then -4+3 or -1.

Answer= - 1

Hope this helps :)
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247x82 using in area model
vovikov84 [41]

247x82=534 5 go in the hundreads place 3 go in the tens place and 4 go in the ones place


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nignag [31]
The answer is: Yes 10-2x is less than 10, x= -5
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