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patriot [66]
3 years ago
14

A car can travel 476 miles on 14 gallons of gas.Write an equation relating the distance d to the number of gallons of gas does t

his car need to travel 578 miles.
Mathematics
1 answer:
bazaltina [42]3 years ago
3 0
Mpg = 476/14 = 34 mpg

d = 578 miles = (34 mpg)(x gallons)

578 = 34x

x = 578/34 = 17 gallons
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\displaystyle \rm 5 ^{7}  \times 5 ^{6}  \times 52

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\displaystyle \rm \: 5 ^{13}  \times 52

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Calculate 8 hours___ minutes
Yuliya22 [10]

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480

Step-by-step explanation:

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Where are the zeros for f(x) = 3 sin 2x on the interval [0, 21)?
garri49 [273]

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0 i think it it is 0

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interval 0 to 21

8 0
3 years ago
Evaluate. 3^√-64/125 <br><br> A.−4/5<br> B.−8/25<br> C.8/25 <br> D.4/5 ​
just olya [345]
The first step to solving this problem is to calculate the cube root. The first step to calculating this is to take the root of the fraction and then take the root of both the numerator and denominator separately. This will look like the following:
\frac{ \sqrt[3]{-64} }{ \sqrt[3]{125} }
An odd root of a negative radicand is always negative,, so the top of the fraction will need to change to the following:
\frac{- \sqrt[3]{64} }{ \sqrt[3]{125} }
For the bottom fraction,, you must write it in exponential form.
\frac{- \sqrt[3]{64} }{ \sqrt[3]{ 5^{3} } }
Now write the top expression in exponential form
\frac{- \sqrt[3]{ 4^{3} } }{ \sqrt[3]{ 5^{3} } }
For the bottom of the fraction,, reduce the index of the radical and exponent with 3.
\frac{ - \sqrt[3]{ 4^{3} } }{5}
Now reduce the index of the radical and exponent with 3 on the top of the fraction.
\frac{-4}{5}
Lastly,, use \frac{-a}{b} =  \frac{a}{-b} = - \frac{a}{b} to rewrite the fraction.
- \frac{4}{5}
This means that the correct answer to this question is option A.
Let me know if you have any further questions
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4 0
3 years ago
Read 2 more answers
The diagram below , not drawn to scale , shows three points R , S and F on the horizontal
Katyanochek1 [597]

The question is an illustration of right-angled triangles.

  • <em>The length of RF is 49.1 m</em>
  • <em>The length of SR is 65.5 m</em>
  • <em>The elevation from S to T is 30 degrees</em>

See attachment for the sketch

<u>(a) Show that RF = 49.1</u>

Considering \triangle FTR

We have:

\tan(R) = \frac{FT}{RF} ---- tangent ratio

This gives:

\tan(27) = \frac{25}{RF}

Make RF the subject

RF = \frac{25}{\tan(27)}

RF = 49.06

Approximate

RF = 49.1

<u>(b) Calculate SR</u>

Considering \triangle FRS

We have:

SR^2 = RF^2 + FS^2 ---- Pythagoras theorem

This gives

SR^2 = 49.1^2 + 43.3^2

SR^2 = 4285.7

Take square roots

SR = 65.5

<u>(c) The elevation from S to T</u>

To do this, we make use of tangent ratio from \triangle FST

\tan(S) = \frac{FT}{FS}

\tan(S) = \frac{25}{43.3}

Take arc tan of both sides

S = \tan^{-1}(\frac{25}{43.3})

S = 30^o

Read more about right-angled triangles at:

brainly.com/question/3770177

8 0
3 years ago
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