We are given the function <span>f(x)=sqrt of (4sinx+2) and is asked to find the first derivative of the function when x is equal to zero.
</span><span>f(x)=sqrt of (4sinx+2)
f'(x) = 0.5 </span><span>(4sinx+2) ^ -0.5 * (4cosx)
</span>f'(0) = 0.5 <span>(4sin0+2) ^ -0.5 * (4cos0)
</span>f'(0) = 0.5 <span>(0+2) ^ -0.5 * (4*1)
</span>f'(x) = 0.5 (2) ^ -0.5 * (4)
f'(x) = -.1.65
Answer:
No solution
Step-by-step explanation:
Im not 100% sure this is right, I looked it up????
Answer:
Step-by-step explanation:
The required dosage in terms of tablets is ...
3680 mg = (3680 mg)/(425 mg/tab) = 8.66 tabs
We don't know how the tablets are "scored", but in my experience they have a groove that facilitates them being cut in half.
We expect the nurse will administer 8 1/2 tablets per day, for a dose of 3613 mg, slightly short of the ordered 3680 mg.
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9 doses will be administered over 8 time intervals of 2 hours, so will take until 16 hours after 7 am. The last (1/2) dose will be at 0700 +1600 = 2300 hours, or 11 pm.
Answer
if a one coin is flippd there is 3 possibility...TH HH TT
here there is 1/3 chance
if 2 coin it is 2/6 that is 1/3 which is 0.33
