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Lisa [10]
3 years ago
8

If f(1) = 7 and f(n) = 5f (n − 1) then find the value of f(5).

Mathematics
2 answers:
VLD [36.1K]3 years ago
5 0

<u>Answer: </u>

f(5) = 4375

<u>Step-by-step explanation: </u>

f(2) = 5f(1) = 5 × 7 = 35

f(3) = 5f(2) = 5 × 35 = 175

f(4) = 5f(3) = 5 × 175 = 875

f(5) = 5f(4) = 5 × 875 = 4375

nevsk [136]3 years ago
3 0

Answer:

f(5) = 4375

Step-by-step explanation:

Given f(n) = 5f(n - 1) and f(1) = 7

This allows us to find the next term in the sequence from the previous term

f(2) = 5f(1) = 5 × 7 = 35

f(3) = 5f(2) = 5 × 35 = 175

f(4) = 5f(3) = 5 × 175 = 875

f(5) = 5f(4) = 5 × 875 = 4375

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Answer:

A

Step-by-step explanation:

Given

\frac{2A}{3} = 8 + 4A

Multiply through by 3 to clear the fraction

2A = 24 + 12A ( subtract 12A from both sides )

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3 0
3 years ago
Could someone pls help??
AnnZ [28]

Answer:

88 cm²

Step-by-step explanation:

Top small rectangular prism: (1 x 2 x 2) + (3 x 2 x 2) + (1 x 3) = 19

Bottom: (6 x 2 x 2) + (2 x 3 x 2) + (5 x 3) + (6 x 3) = 69

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7 0
3 years ago
Please help, super confused :(
alexandr1967 [171]

Answer:

Below.

Step-by-step explanation:

The graph shown is f(x).

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4. The graph 4  is the same shaped graph as drawn but moved 5 units to the right.

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4 0
2 years ago
man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 7 ft/s from a point 500 ft
worty [1.4K]

Answer:

\dot r \approx 8.985\,\frac{ft}{s}

Step-by-step explanation:

Let consider that vertical axis has its positive side oriented to the north and positive side of the horizontal axis has its orientation to the east. Besides, both persons walk at constant rate. Then, displacement formulas are:

Man

y_{1} = (2\,\frac{ft}{s})\cdot t

Woman

y_{2} = - (7\,\frac{ft}{s} )\cdot (t-300\,s)

The minimum distance between the man and the woman can be calculated by means of the Pythagorean Theorem:

r=\sqrt{(500\,ft)^{2}+(y_{1}-y_{2})^{2}}

The rate of change of such distance is:

\dot r = \frac{(y_{1}-y_{2})\cdot (\dot y_{1}-\dot y_{2})}{\sqrt{(500\,ft)^{2}+(y_{1}-y_{2})^{2}}}

The positions and velocities at t = 1200\,s are:

y_{1} = 2400\,ft

\dot y_{1} = 2\,\frac{ft}{s}

y_{2} =-6300\,ft

\dot y_{2} = -7\,\frac{ft}{s}

The rate of change is:

\dot r \approx 8.985\,\frac{ft}{s}

6 0
3 years ago
3x + 1 = y; 2x + 3y = 25
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Substitute the first y= equation into the y of the second. Distribute as needed and solve for x. x=2 and then plug it in to find y. y=7
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4 years ago
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