1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reptile [31]
3 years ago
7

What fraction is equivalent to 123.5℅

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0
123.5\%= 123 \frac{5}{100} \% =123\frac{1}{20}\%= \\\\ = \frac{2.461}{20}\%= \frac{2.461}{20}*\frac{1}{100}= \\\\ =\boxed{\frac{2.461}{2.000}}
You might be interested in
Complete A,B and 6 for 13 points.
kicyunya [14]

Answer:

a) 10

b) The $40+5 dollars for every ticket

c) See below

Step-by-step explanation:

a)

1. Let t=number of tickets

2. Writing an equation

Breaking even means that you earn the same amount of money for both.

40 +5t=70+2t

3. Solving the equation

40 +5t=70+2t

5t-2t=70-40

3t=30

t=10

So the answer to a) is 10.

b)

1. Using an equation

We already know that there are 2 equations for this problem. (40+5t, 70+2t)

So, we will substitute 20 for t.

40+5*20=40+100=140

70+2t=70+2*20=110

2. Comparing equations

140>110, so the first offer is better

C)

The owner lets you choose how you get paid because one option will be better for you, as some days you might not sell many tickets (so you will go with the $70+2 tickets), or some days you might sell many tickets (you will choose the $40+5 dollars/ticket).

3 0
3 years ago
A small business ships specialty homemade candies to anywhere in the world. Past records indicate that the weight of orders is n
FinnZ [79.3K]

Answer with Step-by-step explanation:

Since we have given

n = 16

a) Describe the sampling distribution for the sample mean.

The sampling distribution of the mean is the population's mean from where the items are sampled.

It would be \mu

b. What is the standard error?

s=\dfrac{\sigma}{\sqrt{n}}\\\\s=\dfrac{14}{\sqrt{16}}\\\\s=\dfrac{14}{4}\\\\s=3.5

c. For 90% confidence, what is the margin of error?

Degrees of freedom = v - 1= 16-1 = 15

Using t-table, 1.753 cuts 5% level of significance in each tail.

so, Margin of error would be

1.753\times 3.5\\\\=6.1355

d. Based on the sample results, create the 90% confidence interval and interpret.

So, 90% confidence interval would be

110+6.136\\\\=116.136\\\\and\\\\110-6.136\\\\=103.86

(103.86,116.136)

3 0
3 years ago
What is the surface area if a cube whose edges are 13sqrt(5) cm?
Usimov [2.4K]
By formula of surface area of cube
5 0
3 years ago
Its worth 25 please help and show work
melamori03 [73]

9514 1404 393

Answer:

  3) y = √10

  4) x = 5√2

Step-by-step explanation:

The side ratios of an isosceles right triangle (one of the "special" right triangles) are ...

  1 : 1 : √2

So, for some multiplier k, they can be made to match the sides in your triangles.

__

3) 1·k : 1·k : k√2 = √5 : √5 : y

Clearly, k = √5, so ...

  y = (√5)(√2)

  y = √10

__

4) k : k : k√2 = x : x : 10

  k = 10/√2 = (5√2)/2

  k = x = (5√2)/2

5 0
3 years ago
1. Check all solutions of the equation: 5x(x - 2) = 0
Elenna [48]
1. A and B are both solutions
2. B
3. C
I hope this helps!
7 0
3 years ago
Other questions:
  • Explain how you can tell me 4/5 is in simplest form.
    10·1 answer
  • The mean of a set of credit scores is 4= 690 and g= 14. Which statement must be true?
    14·2 answers
  • Is 8.25 less than 8.250
    6·1 answer
  • An airline estimates that 94% of people booked on their flights actually show up. If the airline books 68 people on a flight for
    12·1 answer
  • Solve for x in the simultaneous equation 2x+y=3 ,5x-2y=12
    11·1 answer
  • The height of one right cylinder is 5 centimeters and its radius is 2 centimeters. The height of the second right cylinder is 20
    14·2 answers
  • Find the missing side
    8·1 answer
  • Please solve! Thanks, i would love an explanation as well!
    7·1 answer
  • Hey y’all should follow it
    10·1 answer
  • Can you help me please
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!