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3 years ago

How did President Truman's Executive Order 9981 show progress toward racial equality?

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

7 0

Answer:

its A

Step-by-step explanation:

Blababa [14]3 years ago

3 0

Answer:

The answer is "The order ended segregation in the military."

Step-by-step explanation:

President Harry S. Truman is the 33rd president of the United States of America. He assumed the President's role after the death of Franklin D. Roosevelt (the 32nd president of the USA). Under his leadership, he was able to abolish the issues concerning the discrimination according to race or religion in the USA's military force. This was backed by the "Executive Order 9981," which he issued in 1948.

The "Executive Order 9981" ended the segregation in the military. Before it was issued, the Black Americans were trained differently from the White Americans. The White Americans were given more priority than the Black ones. This means that the Black Americans have to wait and train longer before they became qualified. Later, it was found out that there was actually no sense in segregating both Americans, since they both performed well in the wartime.

Thus, this explains the answer.

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Island Water Sports provides rental equipment and instruction for a variety of water sports in a resort town. On one morning, a

timofeeve [1]

Answer:

1) C

2) F

3) A

Step-by-step explanation:

Given that : X = number of Wildlife raft Trips to be scheduled.

while Y = number of Group Sailing Lessons to be scheduled.

1) Constraint (1) : 120x + 160y ≥ 1800

Represents the Minimum revenue requirement

2) Constraint (4) : 6x ≥ 30

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Represents The maximum number of captions who can be deployed.

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3 years ago

Graph f(x) = x and g(x) = -1/3x+2 on the same coordinate plane.

Vesnalui [34]

It’s not too hard,

I hope that helps.

6 0

3 years ago

Majesty Video Production Inc. wants the mean length of its advertisements to be 26 seconds. Assume the distribution of ad length

Paladinen [302]

Answer:

a) By the Central Limit Theorem, approximately normally distributed, with mean 26 and standard error 0.44.

b) s = 0.44

c) 0.84% of the sample means will be greater than 27.05 seconds

d) 98.46% of the sample means will be greater than 25.05 seconds

e) 97.62% of the sample means will be greater than 25.05 but less than 27.05 seconds

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation(also called standard error) $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 26, \sigma = 2, n = 21, s = \frac{2}{\sqrt{21}} = 0.44$

a. What can we say about the shape of the distribution of the sample mean time?

By the Central Limit Theorem, approximately normally distributed, with mean 26 and standard error 0.44.

b. What is the standard error of the mean time? (Round your answer to 2 decimal places)

$s = \frac{2}{\sqrt{21}} = 0.44$

c. What percent of the sample means will be greater than 27.05 seconds?

This is 1 subtracted by the pvalue of Z when X = 27.05. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{27.05 - 26}{0.44}$

$Z = 2.39$

$Z = 2.39$ has a pvalue of 0.9916

1 - 0.9916 = 0.0084

0.84% of the sample means will be greater than 27.05 seconds

d. What percent of the sample means will be greater than 25.05 seconds?

This is 1 subtracted by the pvalue of Z when X = 25.05. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{25.05 - 26}{0.44}$

$Z = -2.16$

$Z = -2.16$ has a pvalue of 0.0154

1 - 0.0154 = 0.9846

98.46% of the sample means will be greater than 25.05 seconds

e. What percent of the sample means will be greater than 25.05 but less than 27.05 seconds?"

This is the pvalue of Z when X = 27.05 subtracted by the pvalue of Z when X = 25.05.

X = 27.05

$Z = \frac{X - \mu}{s}$

$Z = \frac{27.05 - 26}{0.44}$

$Z = 2.39$

$Z = 2.39$ has a pvalue of 0.9916

X = 25.05

$Z = \frac{X - \mu}{s}$

$Z = \frac{25.05 - 26}{0.44}$

$Z = -2.16$

$Z = -2.16$ has a pvalue of 0.0154

0.9916 - 0.0154 = 0.9762

97.62% of the sample means will be greater than 25.05 but less than 27.05 seconds

8 0

3 years ago

Rudy has been paying an annual homeowners insurance premium of $1,106.30 ($0.37 per $100 of value) since

Luden [163]

Answer:

c. $1,291.30

Step-by-step explanation:

Calculation what will his new annual homeowners insurance premium be

Insurance premium= [$1,106.30+ ($0.37/ $100*$50,000)]

Insurance premium=$1,106.30+$185

Insurance premium=$1,291.30

Therefore what his new annual homeowners insurance premium will be is $1,291.30

5 0

3 years ago

SOMEONE HELP ME OMG HELPP

sasho [114]

Answer:

-12.90, -12.55, 10.25, 10.75, 12.50

Step-by-step explanation:

this is from least to greatest

3 0

2 years ago