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Rashid [163]
3 years ago
6

Buffy just put some money into a CD that pays 10.1% interest, compounded monthly. According to the rule of 72, in approximately

how many years will she have 4 times the amount of money that she has now?
Mathematics
2 answers:
Grace [21]3 years ago
6 0

Answer:

14.3 years is correct

Step-by-step explanation:

quester [9]3 years ago
5 0
Let the principal be 'x' then the Amount will be 4x.

As the interest is compounded monthly:

Rate of interest = 10.1 % = 10.1/(100*12) = 0.101/12 

Time = 12t

Amount = Principal[1 + Rate/100]

⇒ 4x = x[1 + 0.101/12]¹²t

⇒ 4x/x [1 + 0.008416667]¹²t

⇒ 4 = [1.008416667]¹²t

⇒ log(4) = log[1.008416667]¹²t

⇒ 0.602059991327 = [0.003640014891]¹²t

⇒ 12t = 0.602059991327/0.003640014891

⇒ 12t = 165.400419876

⇒ t = 165.400419876/12

t = 13.78 years  or 13 years 9 months.

So, it is about 13 years 9 months she will have 4 times the amount of money.
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Answer: A Hexagon

Step-by-step explanation:

8 0
2 years ago
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Which of the following is a like radical to RootIndex 3 StartRoot 7x EndRoot?
lana [24]

Answer:

A. 4 (RootIndex 3 StartRoot 7 x EndRoot)  or 4(\sqrt[3]{7x})

Step-by-step explanation:

Given:

A radical whose value is, r_1=\sqrt[3]{7x}

Now, we need to find the like radical for r_1.

Let the like radical be r_2.

As per the definition of like radicals, like radicals are those that can be expressed as multiples of each other.

So, if two radicals r_1\ and\ r_2 are like radicals, then

r_1 = n \times r_2


Where, 'n' is a real number.

Here, r_1=\sqrt[3]{7x}

Now, let us check all the options .

Option A:

4 (RootIndex 3 StartRoot 7 x EndRoot) or r_2=4\sqrt[3]{7x}

Now, we observe that r_2 is a multiple of r_1 because

r_2=4\times \sqrt[3]{7x}\\\\ r_2=4\times r_1..............(r_1=\sqrt[3]{7x})

Therefore, option A is correct.

Option B:

StartRoot 7 x EndRoot or r_2=\sqrt{7x}

As the above radical is square root and not a cubic root, this option is incorrect.

Option C:

x (RootIndex 3 StartRoot 7 EndRoot) or r_2=x\sqrt[3]{7}

As the term inside the cubic root is not same as that of r_1, this option is also incorrect.

Option D:

7 StartRoot x EndRoot or r_2=7\sqrt{x}

As the above radical is square root and not a cubic root, this option is incorrect.

Therefore, the like radical is option (A) only.

4 0
2 years ago
Read 2 more answers
A jeepney ride cost 11 pesos for the first 4 kilometers and each additional integer kilometers adds 3.50 pesos to the fare, use
Nookie1986 [14]

Answer:

f(d)=\left\{ \begin{matrix} 11 & \text{for} & 0< d\leq 4  \\-3+3.5d & \text{for}&  d > 4  \end

Step-by-step explanation:

Cost of first 4 kilometers ride = 11 pesos.

So, for the first 4 km, the fair is constant i.e.

for 1 km the fare is 11 pesos,

for 2 km the fair is also 11 pesos,

similarly, for 3 km of 4 km, the fare is 11 pesos.

Hence, for the distance 0\geq d\geq 4, the fair function,

f(d)=11\cdots(i)

After 4 km, there is an increment of $ 3.50 for each kilometer.

So, the fare function up to 5 kilometers,

f(d)=11+3.5=14.5

So, the fare function up to 6 kilometers, i.e for the distance 5,

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This can be arranged as the fare function up to 6 km,

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Similarly, the fare function up to d kilometer (n>4),

f(d)=11+(d-4)\times3.5

\Rightarrrow f(d)=-3+3.5d\cdots(ii)

Hence, from equations (i) and (ii),

f(d)=\left\{ \begin{matrix} 11 & \text{for}\; 0< d \leq 4  \\-3+3.5d & \text{for}\;  d > 4  \end

8 0
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son4ous [18]
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Blababa [14]

Answer:

-k+8k=7k is the solution

5 0
3 years ago
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