If you can give me more information on this I could help you a bit more respond.
<h3>Answer: Choice C</h3>
RootIndex 12 StartRoot 8 EndRoot Superscript x
12th root of 8^x = (12th root of 8)^x
![\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D)
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Explanation:
The general rule is
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so any nth root is the same as having a fractional exponent 1/n.
Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)
![\sqrt[3]{8} = 8^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%208%5E%7B1%2F3%7D)
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Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so
(1/3)*(1/4)x = (1/12)x
In other words,


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From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this
![8^{(1/12)x} = \sqrt[12]{8^{x}}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20)
![8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D%20)
Direct variation is of the form: y=kx (inverse variation is of the form y=k/x)
Assuming that k is positive :)
y increases as x increases and y decreases as x decreases. There is a direct ratio that is described by k. k=y/x.
Answer:
x:
5x - 29 = 3x+ 19
2x = 48
x = 24°
Angle 1:
180 - (3x+7) = 180 - 79 = 101°
Angle 2:
3x + 7 = 79°
Angle 3:
Same as Angle 1 = 101°
Angle 4:
Same as Angle 1 = 101°
Angle 5:
Same as Angle 2 = 79°
Angle 6:
Same as Angle 5 = 79°
Angle 7:
180 - (5x - 29) = 180 - 91 = 89°
Angle 8:
Same as Angle 7 = 89°
Angles 2 and 3 are Supplementary angles
Answer:
a
Step-by-step explanation:
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