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AlexFokin [52]
3 years ago
5

There is a margin of error on a food survey of +/– 5%. What is the range of the number of students who do not want hot dogs if 8

3 of 127 students said they did not want hot dogs on Wednesdays and there are 900 students at the school? A. 529 to 617 students B. 559 to 647 students C. 559 to 617 students D. 559 to 600 students
Mathematics
2 answers:
dangina [55]3 years ago
8 0
83/127 = x/900
127x = 74700
x = 74700/127
x = 588.1 rounds to 588

588 - 0.05(588) = 558.6 rounds to 559
588 + 0.05(588) = 617.4 rounds to 617

range is C. 559 to 617


scoray [572]3 years ago
5 0

Answer:

Your answer would be C. 559 to 617 students hopefully this helps!

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a trail mix recipe calls for 3/4 a cup of raisins for every 5/8 of a cup of peanuts. how mant peanuts will be needed for 1 cup o
xxTIMURxx [149]

Answer:

5/6 rup of raisins?

Step-by-step explanation

Sorry if that is wrong

4 0
3 years ago
24=9x+4-4x <br> Solve equation. Check your answer.
sammy [17]

Answer:

x=4. Verified, Not wrong.

Step-by-step explanation:

24=9x+4-4x

24 = 5x+4

20-4

5x=20

(divide)

x=4

5 0
2 years ago
Read 2 more answers
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0
3 years ago
What are the domain and range of this relation? {(3, -9), (11,21), (121,34), (34,1), (23,45)}
Simora [160]

Answer:

domain = ( 3, 11, 121, 34, 23)

range = ( 21, 34, 1, 23)

7 0
3 years ago
A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure anti
Murrr4er [49]

With amounts measured in gallons, let

x = amount of 65% antifreeze

y = amount of 90% antifreeze

1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.

To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have

x + y = 120 … … … … … [total volume of antifreeze solution]

0.65x + 0.90y = 96 … [total volume of pure antifreeze]

Solve the first equation for y :

y = 120 - x

Substitute this into the second equation and solve for x :

0.65x + 0.90 (120 - x) = 96

0.65x + 108 - 0.90x = 96

0.25x = 12

x = 48

Solve for y :

y = 120 - 48

y = 72

6 0
2 years ago
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