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3 years ago

What is 60m to 90m using fraction notation and reduce

Mathematics

1 answer:

aliya0001 [1]3 years ago

5 0

$\dfrac{60~m}{90~m} = \dfrac{6}{9} = \dfrac{2}{3}$

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Explain how you could estimate 22% of 78 to check if your answer is reasonable.

choli [55]

you can find 10 percent by dividing 78 by 10 which is 7.8. Then you double that to find 20 percent. That will make you find 20 percent! close to 22

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4 years ago

A spotlight on a 3.0 m stand shines on the surface of a swimming pool. The beam of light hits the water at a point 7.0 m away fr

Ede4ka [16]

The angle the beam makes with the pool surface is 29.72°.

Step-by-step explanation:

The spotlight and surface of a swimming pool makes a 90 degree angle.

Spotlight stand is 3m (Opposite)

Beam of light hits the water 7m away from the base of light (base)

Angle = ?

<u>Use sin to solve</u>

Formula:

Tan (Angle) = $\frac{Opposite}{Base}$

Solution:

Sin (Angle) = $\frac{3}{7}$

Angle = $tan^{-1}$ (0.571)

Angle = 29.72°

Therefore, the angle the beam makes with the pool surface is 29.72°.

Keyword: Angle

Learn more about angle at

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3 years ago

An expression is shown. -8+4-7-9-2+(-5) What is the value of the expression?

Colt1911 [192]

Answer:

-27

Step-by-step explanation:

-8+4-7-9-2+(-5)

= -4-7-9-2-5

= -20-2-5

= -27

4 0

3 years ago

Help plzzzz ASAPPPPP

notsponge [240]

Answer:7.875 or 7 7/8

Step-by-step explanation:

3 0

3 years ago

Simulate the rolling of two dice 10,000 times. (b) Identify which rolls of the dice are in the event A, the dice add up to a per

dexar [7]

Answer:

Answer explained below

Step-by-step explanation:

(a)

Simulate the rolling of two dice 10,000 times D1 and D2 are the 10,000 results of roll of dice 1 and dice 2.

D1 = sample(c(1:6), 10000, replace = TRUE)

D2 = sample(c(1:6), 10000, replace = TRUE)

Sum = D1 + D2

(b)

The event A, the dice add up to a perfect square (4 or 9).

A = Sum[Sum == 4 | Sum ==9]

Proportion of A, P(A) = 0.189

length(A) / length(Sum)

(c)

The event B, the dice add up to an even number.

B = Sum[Sum %% 2 == 0]

Proportion of B, P(B) = 0.5049

length(B) / length(Sum)

(d)

The rolls are in A ∩ B (common to both A and B)

> intersect(A,B)

[1] 4

The proportion that are in A ∩ B is 0.0792

length(Sum[Sum == 4]) / length(Sum)

P(A) * P(B) = 0.189 * 0.5049 = 0.0954

The proportion in A multiplied by the proportion that are in B is not equal to P(A ∩ B)

(e)

Of the rolls in which B occurs, the proportion of those rolls are also in A is 0.4190476

length(Sum[Sum == 4]) / length(A)

This proportion is greater than the P(A) calculated in part (b).

4 0

3 years ago