Which set is more variable? How do you know?

Can you help me solve this please step by step

eimsori [14]

First, the values of 2sqrt(3) or 3sqrt(3) are not even twice the length of the given base, 3.

Next, I would say that 6 is the better answer than 12, assuming that the triangle is”drawn-to-scale”.

Finally, I think the hypotenuse is 6.

8 0

2 years ago

Combine like terms to write an equivalent expression for 2( 4y^2 + 6x - 2y^2 + 12x.)

natima [27]

8y^2 + 12x - 4y^2 + 24x
= 4y^2 + 36x

3 0

3 years ago

Plz help I beg I will give Brian list and points

just olya [345]

The probability is 4 out of 14

6 0

3 years ago

Read 2 more answers

In Bangor it’s -3 F in Fairbanks it’s -12 F in Fargo it’s -8 F and in Calgary it’s -15 F in which city is to the coldest?

jonny [76]

Answer:

Calgary is the coldest

Step-by-step explanation:

The simple way to determine this will be to change the value of temperatures given in Fahrenheit to Celsius

32 F = 0°C

Formula to apply will be (T-32)×5/9 -------------where T is temperatures in Fahrenheit

Bangor is -3F-------------------change to Celsius

(-3-32)×5/9 =-35 × 5/9 = -19.44°C

Fairbanks is -12 ------------------------change to Celsius

(-12-32)×5/9 = -44 × 5/9 = -24.44°C

Fargo is -8 F ---------------------Change to Celsius

(-8-32)×5/9= -40×5/9 = -22.22°C

Calgary is -15 F-------------------------Change to Celsius

(-15-32)×5/9 = -47×5/9 = -26.11°C--------------coldest

3 0

3 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

3 years ago