For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller
ok so
first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and
hypontuse is 6 more than shorter
c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero
b-9=0
b=9
b+3=0
b=-3
fasle, legnths cannot be negative
answer is shorter side=9 cm
Answer:
1) x=3, y=-3
Step-by-step explanation:
10x + 7y = 9 —— (1)
-4x -7y = 9 —— (2)
(1) + (2)
6x = 18
x = 18/6
x = 3
put x=3 in (1)
10(3) + 7y = 9
30 + 7y = 9
7y = 9 - 30
7y = -21
y = -21/7
y = -3
please give me brainlist if it is helpful for you
⅚. You first find out how many feet are in a yard (three). Then you write the fraction- 10/12. Then you reduce. The number two can evenly go into both of those numbers. Ten divided by two is five. Twelve divided by two is six. So, your final answer is ⅚.
Refrection of (-20, 4) across x-axis gives (-20, 4) = (-20, -4)
Refrection of (-20, 4) across y-axis gives (20, 4)
Refrection of (-20, 4) across y = -x gives (20, -4)
Refrection of (-20, 4) across y = 7 gives (20, 10)
