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blondinia [14]
3 years ago
15

The Senior class is taking a trip to an amusement park. They received a special deal where for every 3 tickets they purchased th

ey received one free ticket. 3 tickets cost $53.25. The total purchase of tickets cost $1384.50. How many tickets did they receive?
Mathematics
1 answer:
Marianna [84]3 years ago
4 0
461+153 will be your answer
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Is 30/12 and 40/16 equivalent?
Flura [38]
30/12 in simplest form is 5/2 (cause 6 * 5 = 30 and 6 * 2 = 12)
40/16 in simplest form is 5/2 (cause 8 * 2 = 16 and 8 * 5 =40)
so yes they're equivalent;
30/12 = 40/16
Hope that helps :D have a nice day!
5 0
3 years ago
Read 2 more answers
A busy customer service agent handled 20 emails in
nignag [31]

20 mails in 1/4 day (0.25 day)

-> 1 day = 20/0.25 = 80 emails

4 0
3 years ago
You have determined that a statistical study is biased. What does this mean? A. Errors were made in data collection. B. Particip
Natasha2012 [34]

Answer:

Participants were lead to respond in a specific way.

Explanation:

Bias (the verb) is to show influence or prejudice about a certain thing and can cause people to change how they act or what they do.

3 0
3 years ago
You have P = 472 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the r
Ray Of Light [21]
The width would be 236 and the lengths would be 118

Use the equations 2L+W=472 and W*L=MAX
Change the first equation to W=472-2L and plug this into the other equation
(472-2L)(L)=MAX
472L-2L^2=M (take derivative)
472-4L=0 (set to 0 to find the max value)
4L=472 
L=118 
Plug into original to get W=236

Hope this helps!
4 0
3 years ago
Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

6 0
3 years ago
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