All categories

2 years ago

The campers in cabin b walked 2/3 of the way to silver stream. how many miles did they walk

Mathematics

2 answers:

jasenka [17]2 years ago

6 0

2/3 of 8 miles is 5 and 1/3 miles. So they walked about 5 and 1/3 miles there.

Natali [406]2 years ago

5 0

They walked 5miles andar 1/3

You might be interested in

What is 20% of 120 ??? HELP ME

maksim [4K]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Taliyah needs to buy 43 favors that cost 2.75 each.Estimate the total cost by rounding each number of favors to thge nearest who

nika2105 [10]

Answer: $129

Step-by-step explanation: First, you round 2.75 up to 3 and then you multiply by 43. Boom, $129.

5 0

3 years ago

The ratio of the side length of a square to the square's perimeter is always 1 to 4.

makvit [3.9K]

Answer:

Side length of square (inches): 1 ,2, 4, 7

Perimeter of square (inches). : 4, 8, 16, 28

Step-by-step explanation:

Ratio is 1:4 (S:P).

So:

#:8, #=2. This is because 2/8 and 1/4 both = 0.25.

#:16, #=4. 4/16=0.25

7:#, #=28. 4x7=28, 7/28=0.25

Hope that helps

7 0

2 years ago

The area of a square garden is 1/49 km ^2. How long is each side?

babunello [35]

1/49=x^2 where x is the side of the square

1/49=(1/7)^2, so the side length of the square is 1/7

3 0

3 years ago

The angle of depression from the top of a cruise ship to the top of a sailboat is 22. Sitting above water, the cruise ship is 23

dusya [7]

Answer:

The distance between the cruise ship and the sail boat is 517 feet.

Step-by-step explanation:

The cruise ship is 236 feet tall, and the sailboat is 236 tall; this means the distance between the top of the cruise ship and the top of the sail boat is

236 feet - 27 feet = 209 feet.

We also know that the angel of depression from the top of the cruise ship to the bottom of the cruise ship is 22°. This forms a right triangle as shown in the figure attached.

Now from trigonometry we get:

$tan \: \theta = \dfrac{209}{d}$

$d= \dfrac{209}{tan\:\theta }$

$\boxed{d=517ft}$

The distance between the cruise ship and the sailboat is 517 feet.

3 0

3 years ago