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Nastasia [14]
3 years ago
13

The table shows the relationship between two variables. which selection describes the relationship?

Mathematics
2 answers:
Phantasy [73]3 years ago
8 0
Linear; increasing
Hope tuhis helps

Liula [17]3 years ago
4 0

Answer:

The relationship between two variables is decreasing and linear.

Step-by-step explanation:

From the given table it is notice that the function passing through the points (1,5), (2,-1), (3,-7) and (4,-13).

Slope of the function between first two points (1,5) and (2,-1) is

m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-5}{2-1}=-6

Slope of the function between last two points (3,-7) and (4,-13) is

m_2=\frac{y_2-y_1}{x_2-x_1}=\frac{-13+7}{4-3}=-6

The rate of change or slope of the function is constant.

From the given table it is noticed that the values of y decreased by 6 units as the values of x increased by 1 units.

Since the rate of change constant and negative, therefore the relationship between two variables is decreasing and linear.

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3. Write an equation of a line that is perpendicular to the line x – 2y = 8.
xenn [34]

Answer:

y=0.5x+40

Step-by-step explanation:

Copy the  equation.

x-2y=8

Subtract x from both sides.

-2y=-x-8

Divide both sides by -2.

y=0.5x+4

Now we know the slope is 0.5.

Any line with a slope of 0.5 will be perpendiculr to the original line.

One that you can use is y=0.5x+40.

7 0
3 years ago
Segment CB is a____
Dahasolnce [82]

Answer:

Radius

Step-by-step explanation:

CB = AB/2

Since AB is the diameter, CB is a radius

5 0
3 years ago
ASAP please
Slav-nsk [51]

Answer:

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3 0
3 years ago
Lines m and p are perpendicular if the slope of line is 1, 25th what is the slope of line p
Rainbow [258]
-1 is the opposite reciprical (perpendicular)
7 0
2 years ago
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
coldgirl [10]

Answer:

c is all the points in the open interval (0,25)

Step-by-step explanation:

Here given is a function

f(x) =x, which is continuous  in the interval [0,25] and differentiable in (0,25)

Mean value theorem says there exists at least one c in the interval (0,25) such that

f'(c) = \frac{f(25)-f(0)}{25-0}

We have

f(25)=25 and f(0) = 0\\f'(c) = 1

For the given function

f'(x) =1

Hence we have c equals all the points in the open interval (0,25)

7 0
3 years ago
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