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UNO [17]
3 years ago
6

Find the diameter of a circle with an area of 676π square centimeters.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0
A = \pi r^2 \\
676\pi = \pi r^2 \\
r = \sqrt{676} = 26

Therefore, the diameter is twice of that:
52 centimeters.
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Domain and range of the function f(x)= 7x^5<br> PLEASE HELP I LITERALLY CANT DO IT
sineoko [7]

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

The domain is all x values, and the range is all y values.

<u><em>Domain:</em></u>

The domain is all real numbers except where the slope is undefined (a vertical line). In this case, no number makes the expression undefined, so the domain is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

<em><u>Range:</u></em>

The range is the set of all valid values. Graph the line and check. Since all values of y are valid, the range is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

:Done

3 0
2 years ago
an earthquake measures 3.6 on the richter scale. what is the amount of energy (ergs) released by the earthquake? give an exact a
Alisiya [41]
We have that 

<span>log10 E = 4.4 + 1.5<span>M
</span></span>E=<span>the released energy in Joules (J)
M= </span><span>earthquake measures---------- > 3.6
</span>log10 E = 4.4 + 1.5*3.6
log10 E = 9.8----------> E=10^(9.8)= 6.309573444 x10^9 J
<span>
the answer is  </span>6.309573444 x10^9 J<span>

</span>
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