Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
- : μ=523
- : μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
radius of ½ circle = d : 2
= 6in : 2 = 3in
Total area = Rectangle area + ½Circle area + Triangle area
= (l×w) + ½(π×r²) + (½×b×h)
= (10×6) + ½(π×3²) + (½ × (14-10) × 6)
= 60 + 14.14 + 12 = 86.14in
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Answer : 86.14in</h3>
<em>See</em><em> </em><em>the</em><em> </em><em>bold</em><em> </em><em>one</em><em> </em><em>in</em><em> </em><em>line</em><em> </em><em>2</em><em> </em><em>of</em><em> </em><em>total</em><em> </em><em>area</em><em>,</em><em> </em><em>thats the</em><em> </em><em>formula</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>shape</em><em>.</em>
30/18 = 10/6 = 5/3 hope this helps!
It increased a total of 4 inches.