Question

The population of a town is 100,000 in 2014. The population increases at a rate of 4.5 percent every year. What will the population of the town be in 2020? Round you answer to the nearest whole number.

Answer 1

The population of a town is "130226"  in 2010.

Step-by-step explanation:

Given,

The population of a town in 2014 (P) = 100,000,  the population increases at a rate (r) = 4.5 % and time (n) = 6 years

To find, the population of the town in 2010 = ?

We know that,

Amount (A) =$P(1+\dfrac{r}{100} )^n$

$=100,000(1+\dfrac{4.5}{100} )^6$

$=100,000(1+0.045)^6$

= 100,000 × 1.3022

= 130226

∴ The population of the town in 2010 = 130226

Thus, the population of a town is "130226"  in 2010.