Question

The force of gravity between two objects is given by  Fg =

Answer 1

Hello from MrBillDoesMath!

Answer:

The y axis

Discussion:

The equation is

F =   (G (m1)(m2)) / r^2

so the question is equivalent to asking what is the asymptote of 1/r^2 as r approaches 0, The asymptote is the y axis as shown in the attachment where 1/r^2 is graphed.

Thank you,

MrB

Answer 2

Answer with explanation:

The force of gravity between two objects is given by

   $F_{g}=\frac{-Gm_{1}m_{2}}{r^2}$

Replacing , force by , y and product of -G  the gravitational constant, masses $m_{1}, m_{2}$ by t,the above equation reduces to,

  $y=\frac{t}{x^2}$

Horizontal Asymptote, is, y=0

 $y= \lim_{x \to \infty} f(x)\\\\y = \lim_{x \to \infty} \frac{1}{x^2}\\\\y=0$

And Vertical Asymptote is, x=0

 $x= \lim_{y \to \infty} f(y)\\\\x = \lim_{y \to \infty} \frac{-1}{\sqrt{y}}\\\\x=0$

The meaning of vertical asymptote in context of the graph of the function is  ,that when Distance between two objects reduces to Zero, the force of attraction between two bodies, reduces to zero.