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3 years ago

Do you know what K=2r-s is

1 answer:

3 0

Our goal is to get r all by itself on one side of the equals sign. To do this, we'll first add s to both sides

k=2r-s

+s +s

k+s=2r

Now, to get r alone, we need to get rid of the 2. Since 2 is multiplied by r, we need to divide it from both sides to get r alone.

k+s=2r

/2 /2

(k+s)/2=r

Since there are no numbers, that's the final answer.

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I really need help with this and how find the Surface area and Lateral area and what is the length and width for both of the fig

Ksenya-84 [330]

Answer:

ok fking fk it ill just tell you, the most affordable way is doing it as a 4*3 package, the length will be 16, width 12, and the height 5. the area will be 960in^3, and the SA will be 664 in^2

Step-by-step explanation:

6 0

4 years ago

For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

3 0

3 years ago

Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble

vagabundo [1.1K]

How you would solve this is move the letter so that it would say h=a/b so that means the answer is 330/22= 15 the answer is 15

5 0

3 years ago

(30 POINTS)

Shalnov [3]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 3 more answers

* During a 10 year period, the number of people living in Sherbury increased by 5% to 20 265

eimsori [14]

Answer:During 10years ago the number of people living in Sherbury increased by 965 while the number of people living in Yaston increased by 942

Step-by-step explanation:

During the 10 year period,

Let x= increase in the number of

people living in Sherbury

y=number of people living in Sherbury before the increase

Therefore,

5/100 * y = x

0.05y=x

And

x + y = 20265

But y=20x

x + 20x =20265

21x=20265

x=965

During 10years ago the number of people living in Sherbury increased by 965.

Likewise

Let

a=increase in the number of

people living in Yaston

b=number of people living in Yaston before the increase

7.5/100 * b = a

0.075b = a

b=13.33a

a + b = 13502

a + 13.33a=13502

14.33a=13502

a=942

During 10years ago the number of people living in Yaston increased by 942.

Conclusion

During 10years ago the number of people living in Sherbury increased by 965 while the number of people living in Yaston increased by 942.

8 0

3 years ago