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Aleonysh [2.5K]
3 years ago
9

Do you know what K=2r-s is

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0
Our goal is to get r all by itself on one side of the equals sign. To do this, we'll first add s to both sides

k=2r-s

+s   +s

k+s=2r

 

Now, to get r alone, we need to get rid of the 2. Since 2 is multiplied by r, we need to divide it from both sides to get r alone.

 

k+s=2r

/2    /2

 

(k+s)/2=r

 

Since there are no numbers, that's the final answer.

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Ksenya-84 [330]

Answer:

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Step-by-step explanation:

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For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
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\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
3 years ago
Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble
vagabundo [1.1K]
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5 0
3 years ago
(30 POINTS)
Shalnov [3]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Read 3 more answers
* During a 10 year period, the number of people living in Sherbury increased by 5% to 20 265
eimsori [14]

Answer:During 10years ago the number of people living in Sherbury increased by 965 while the number of people living in Yaston increased by 942

Step-by-step explanation:

During the 10 year period,

Let x= increase in the number of

people living in Sherbury

y=number of people living in Sherbury before the increase

Therefore,

5/100 * y = x

0.05y=x

And

x + y = 20265

But y=20x

x + 20x =20265

21x=20265

x=965

During 10years ago the number of people living in Sherbury increased by 965.

Likewise

Let

a=increase in the number of

people living in Yaston

b=number of people living in Yaston before the increase

7.5/100 * b = a

0.075b = a

b=13.33a

a + b = 13502

a + 13.33a=13502

14.33a=13502

a=942

During 10years ago the number of people living in Yaston increased by 942.

Conclusion

During 10years ago the number of people living in Sherbury increased by 965 while the number of people living in Yaston increased by 942.

8 0
3 years ago
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