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3 years ago

Do you know what K=2r-s is

1 answer:

3 0

Our goal is to get r all by itself on one side of the equals sign. To do this, we'll first add s to both sides

k=2r-s

+s +s

k+s=2r

Now, to get r alone, we need to get rid of the 2. Since 2 is multiplied by r, we need to divide it from both sides to get r alone.

k+s=2r

/2 /2

(k+s)/2=r

Since there are no numbers, that's the final answer.

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F(x) =3x+4=g(x)=2x+1 /x_4:find the (fog)?

Kaylis [27]

Answer:

Step-by-step explanation:

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3 years ago

A seed company planted a floral mosaic of a national flag. The perimeter of the flag is 2,120 ft Determine the flag's width and

Nookie1986 [14]

Answer:

the width is 360 ft

Step-by-step explanation:

The computation of the width of the flag is shown below:

Let us assume the width be x

So the length would be x + 340

And, the perimeter is 2,120 ft

So the formula is

Perimeter = 2(length + width)

2,120 = 2(x + 340 + x)

2,120 = 2x + 680 + 2x

2,120 = 4x + 680

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3 years ago

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IRINA_888 [86]

Answer:

168

Step-by-step explanation:

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3 years ago

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son4ous [18]

Answer:

<h2 />

Step-by-step explanation:

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2 years ago

A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get

julsineya [31]

I have an expression

$\sigma = \sqrt{p(1-p)/n}$

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

$E( (b-p)^2 ) = (-p)^2(1-p) + (1-p)^2p = p(1-p)$

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

$\sigma = \sqrt{p(1-p)/n}$

Plugging in the numbers,

$\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%$

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

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4 years ago