Question

Dilate the the triangle, scale factor = 3 (positive 3, ignore the

Answer 1

Answer:

The rule of dilation is $P'(x,y) = 3\cdot P(x,y)$.

The vertices of the dilated triangle are $A'(x,y) = (-21, -18)$, $B'(x,y) = (-15,-10)$ and $C'(x,y) = (-3,-15)$, respectively.

Step-by-step explanation:

From Linear Algebra, we define the dilation by the following definition:

$P'(x,y) = O(x,y) + k\cdot[P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation, dimensionless.

$k$ - Scale factor, dimensionless.

$P(x,y)$ - Original point, dimensionless.

$P'(x,y)$ - Dilated point, dimensionless.

If we know that $O(x,y) = (0,0)$, $k = 3$, $A(x,y) = (-7,-6)$, $B(x,y) = (-5,-2)$ and $C(x,y) =(-1,-5)$, then dilated points of triangle ABC are, respectively:

$A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)]$ (2)

$A'(x,y) = (0,0) + 3\cdot [(-7,-6)-(0,0)]$

$A'(x,y) = (-21, -18)$

$B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)]$ (3)

$B'(x,y) = (0,0) + 3\cdot [(-5,-2)-(0,0)]$

$B'(x,y) = (-15,-10)$

$C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)]$ (4)

$C'(x,y) = (0,0) +3\cdot [(-1,-5)-(0,0)]$

$C'(x,y) = (-3,-15)$

The rule of dilation is:

$P'(x,y) = 3\cdot P(x,y)$ (5)

The vertices of the dilated triangle are $A'(x,y) = (-21, -18)$, $B'(x,y) = (-15,-10)$ and $C'(x,y) = (-3,-15)$, respectively.