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SashulF [63]
3 years ago
8

How do I become smarter in all subjects? I missed out on a lot of education growing up, I'm still really smart in what I know an

d I plan to go to college.. Give your boy some advice!
SAT
2 answers:
Taya2010 [7]3 years ago
6 0
The best way to become smarter in all subjects is
•Don't give up--that is the main thing you have to remember, no matter how hard it is or how difficult it is for you to understand. You will understand eventually, it takes time.
•Take a few weeks (2 at the most) to cover one topic of a subject. That way you can get more knowledge of what the topic is about and get a great grasp of the information to help you in life.
•Ask adults if you have any questions about something--the best thing to do is if you don't understand something either ask Brainly or your parents because most likely they will have the answer.
•Don't slack off--keep practicing even if you want to go hide under the sheets and watch Netflix, it will really help if you go over everything and practice what you've learned.
Stay encouraged--no matter what other people say, you can do this. Get your education and rule all the subject!
I really hope this helped. If it didn't sorry and I will try harder next time, good luck on mastering all of the subjects and getting into college.
I'm rooting for you!
lilavasa [31]3 years ago
4 0
You need to pay attention to all your teachers because what they say are very important and don't goof of or talk in class
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an automated tool known as log can consolidate system logs, perform comparative analysis and detect common occurrences or behavi
dalvyx [7]

Log analysis tools  is an automated tool known as log can consolidate system logs, perform comparative analysis and detect common occurrences or behavior of interest

<h3>What is a log analysis tool?</h3>

Log analysis tools are known to be tools that aids in the generating of web, streaming and other kinds of mail server statistics graphically.

Hence, Log analysis tools  is an automated tool known as log can consolidate system logs, perform comparative analysis and detect common occurrences or behavior of interest

Learn more about automated tool from

brainly.com/question/24227940

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2 years ago
The price of a cellphone was discounted by 25%
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3 years ago
company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul
lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

  • <em>The proportion of Good TV set is 0.67</em>
  • <em>The number of ways of selecting 5 from 6 TV sets is 6</em>
  • <em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

n = 6

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

Good = 4

So, the proportion (p) that are good are:

p = \frac{Good}{n}

p = \frac{4}{6}

p = 0.67

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 5

So, we have:

^6C_5 = \frac{6!}{(6 - 5)!5!}

^6C_5 = \frac{6!}{1!5!}

^6C_5 = \frac{6 \times 5!}{1 \times 5!}

^6C_5 = \frac{6}{1}

^6C_5 = 6

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 4

So, we have:

^6C_4 = \frac{6!}{(6 - 4)!4!}

^6C_4 = \frac{6!}{2!4!}

^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}

^6C_4 = \frac{30}{2}

^6C_4 = 15

So, the table is as follows:

\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

p = \frac{Good}{n}

<u>(d) The sampling distribution</u>

In (a), we have:

p = 0.67 --- proportion of Good TV

The sampling error is calculated as follows:

SE_n = |p - p_n|

So, we have:

\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]

Read more about sampling distributions at:

brainly.com/question/10554762

3 0
3 years ago
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