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cupoosta [38]
3 years ago
13

Which of the undefined terms is used to define the term parallel lines

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0
<span>x.line is the correct answer</span>
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Stuck, anyone can help?
expeople1 [14]

Answer:

Step-by-step explanation:

\sqrt{x-3} = x - 5 ( x ≥ 3 )

( \sqrt{x-3} )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

x_{1} = 7

x_{2} = 4

Check the answer:

1). x = 7

\sqrt{7-3} = 7 - 2

√4 = 2

2 = 2

2). x = 4

\sqrt{4-3} = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.

6 0
2 years ago
Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

5 0
3 years ago
Least to greatest !?
Bad White [126]
The lengths are \frac{5}{6} \frac{5}{12} and \frac{1}{3}
finding the LCM we get
\frac{10,5,4}{12}
arranging them 
 \frac{1}{3} \frac{5}{12} and \frac{5}{6}
6 0
3 years ago
HELP ME PLEASE!!!
Pavel [41]

Answer:

Lo siento amigo mío pero ha llegado el momento. Necesitas hacer tu propia tarea porque la profunda y oscura verdad es ... nadie te ayudará cuando falles en la prueba. Por eso estoy aquí para llevarte. Deja de pedir respuestas y pruébalas tú mismo. Pídele ayuda a tu maestro. Pero deja de pedirle respuestas a la gente. Eso es definitivamente una trampa.

Step-by-step explanation:

7 0
3 years ago
Find the slope of a graph<br> I'll GIVE BRAINLESS
tester [92]

Answer: 5/4

Step-by-step explanation:

8 0
3 years ago
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