Please help I’ll mark you as brainliest if correct!

I will give braliest to the person who finishes this first.

labwork [276]

Answer:

1. Ba + B3

2. 100 + 5g

3. 25y - 14

4. 6 + 2x

5. 2Ba + B

6. 8h - 12

7. 28e + 24

8. -20y + 72

9. 39 - 21w

10. 3x + 6

11. 5 + 2y

12. 3a + 10

13. 4k + 7

14. 42 + 11r

15. 13w + 15

16. 5a + 34

17. 22f - 12

18. 9x + 2

Step-by-step explanation:

I hope this was helpful! <3

Could I get brainliest?

5 0

3 years ago

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Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

How many possible outcomes are there when flipping a coin 9 times?<br> its 512 right?

BabaBlast [244]

Yes, I believe so.

Hope this helps

5 0

4 years ago

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Help me find the slope

AleksandrR [38]

The slope of the smaller triangle is 5/4 (5 over 4)
The slope of the larger triangle is 10/8 (10 over 8)
They are equal as 10/8 can be reduced to 5/4

4 0

4 years ago

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Need help please.........thank you

crimeas [40]

A²-b²=(a-b)(a+b)
4x² - 25= (2x)²- 5² =(2x-5)(2x+5)
You do not have this choice, so the answer is D.None of the above.

6 0

3 years ago

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